Passing array as arguments in TypeScript

Question

I have two methods:

static m1(...args: any[]) {
    //using args as array ...
}

static m2(str: string, ...args: any[]){
    //do something
    //....

    //call to m1
    m1(args);
}

The call to m1(1,2,3) works as expect. However, the call m2("abc",1,2,3) will pass to m1([1,2,3]), not as expect: m1(1,2,3).

So, how to pass args as arguments when make call to m1 in m2?

Rick Love · Accepted Answer · 2016-03-17 16:39:29Z

141

Actually, using the ... again when calling the method will work.

It generates the apply call for you in javascript.

static m1(...args: any[]) {
    //using args as array ...
}

static m2(str: string, ...args: any[]){
    //do something
    //....

    //call to m1

    // m1(args);
    // BECOMES
    m1(...args);
}

answered Mar 17, 2016 at 16:39

Rick Love

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1 Comment

Rick Love Over a year ago

Yeah, this probably didn't work when the question was first asked. But this is the best way now.

user703016 · Accepted Answer · 2013-12-07 15:57:52Z

23

Use Function.prototype.apply:

T.m1.apply(this, args);

Where T is the enclosing class of m1.

edited Dec 7, 2013 at 15:57

answered Dec 7, 2013 at 15:36

user703016

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3 Comments

tnx247 Over a year ago

Yes, passing this in this case will make this within m1 refer to object of outer context (m2). Still need a way to refer to this of m1 within m1.

tnx247 Over a year ago

I'm using 0.9.5, but my sample is incorrect. Actually, my code is A.m1() and B.m2(), so I fixed by call m1.apply(A,args), and it works great. Thank you again!

Chklang Over a year ago

Not use this method. It's javascript, not typescript. Use the response by Rick Live :)

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