How can I do this in python:
x = [1,2,3,4,5,6]
for i in x:
if i == 4:
-restart the loop from beginning-
else:
print i
So here it will print till 4 then repeat the loop
6 Answers
What about this:
x = [1,2,3,4,5,6]
restart = True
while restart:
for i in x:
# add any exit condition!
# if foo == bar:
# restart = False
# break
if i == 4:
break
else:
print i
1 Comment
noobninja
Could also put
print i before the if statement, and remove elseSomething like this perhaps? But it will loop forever...
x = [ ..... ]
restart = True
while restart:
for i in x:
if i == 4:
restart = True
break
restart = False
print i
Comments
You can't directly. Use itertools.cycle
for idx, val in enumerate(itertools.cycle(range(4))):
print v
if idx>20:
break
idx is used to break infiniteloop
Comments
Just wrap in a while statement.
while True:
restart = False
for i in x:
if i == 4:
restart = True
break
else:
print i
if not restart:
break
Comments
With a while loop:
x=[1,2,3,4,5,6]
i=0
while i<len(x):
if x[i] == 4:
i=0
continue
else:
print x[i]
i+=1
Comments
I would use a recursive function for that
def fun(x):
for i in x:
if i == 4:
fun(x)
else:
print i
return;
x = [1,2,3,4,5,6]
fun(x)
5 Comments
Joel Cornett
You're going to get a
RuntimeError for exceeding the maximum recursion limit very quickly. The default is 1000.
freude
How many times does author want to repeat?
Corley Brigman
recursive functions are dangerous for high values of recursion, and are a lot hard to integrate exit conditions into.
freude
ok, I agree, I remove the post than?
qwertynl
You click delete @freude
itertools.cycle.while True: for i in range(1, 5):?