I have an array of objects structured like so (this is just example) and an array of id:
var array_objects=[
{id:'a',value:1},
{id:'b',value:2},
{id:'c',value:2},
{id:'d',value:3}
];
var array =['b','c','a','d'];
I wish to reorder array_objects the same way array is ordered. The order in the array can change each time. How to do this?
A simple solution:
array_objects.sort(function(a,b){
return array.indexOf(a.id)-array.indexOf(b.id)
})
If you have a very big array and you want something really fast, here's a variant not calling indexOf:
var m = array.reduce(function(r,k,i){ return r[k]=i,r },{});
array_objects.sort(function(a,b){ return m[a.id]-m[b.id] });
Easiest to generate a new array.
var arr2 = [], i;
for (i = 0; i < array.length; ++i)
arr2[array.indexOf(array_objects[i].id)] = array_objects[i];
If it's important to use the same reference, you can do some magic with splice
var i;
for (i = 0; i < array.length; ++i)
array_objects[array.indexOf(array_objects[i].id) + array.length] = array_objects[i];
array_objects.splice(0, array.length);
I think this quite simple, try this:
array_objects.sort(function(a,b){
return (a.id) > (b.id)
});
array, referencingarray_objectsto create a new, sorted, array of objects