How to pass extra parameter in ajax call to php using jQuery DataTables?

Question

Here is my code

 $(document).ready(function() {
            var dataTable =  $('#student-grid').DataTable( {
                responsive: {
                    details: {
                        renderer: function ( api, rowIdx ) {
                            var data = api.cells( rowIdx, ':hidden' ).eq(0).map( function ( cell ) {
                                var header = $( api.column( cell.column ).header() );
                                return  '<p style="color:#00A">'+header.text()+' : '+api.cell( cell ).data()+'</p>';
                            } ).toArray().join('');

                            return data ?    $('<table/>').append( data ) :    false;
                        }
                    }
                },
                processing: true,
                serverSide: true,
                ajax: "borrowedBookNew.php" // json datasource
            } );

        } );

I want to pass a new parameter to my php file and get a new result.

This question is very clear and should not be closed.

Gyrocode.com
– Gyrocode.com

2015-07-12 20:13:41 +00:00
Commented Jul 12, 2015 at 20:13 — Gyrocode.com
– Gyrocode.com, Commented Jul 12, 2015 at 20:13

Thomas · Accepted Answer · 2015-07-12 12:19:35Z

5

You can pass additional data by setting the ajax parameter to an object:

$('#student-grid').dataTable({
    // ...
    ajax: {
        url: 'borrowedBookNew.php',
        data: {
            customField: 'customValue'
        }
    }
});

You can also pass data a function that receives the current data as an object which you can manipulate. This is especially useful for adding dynamic data that isn't available at page load.

Source: http://datatables.net/examples/server_side/custom_vars.html

answered Jul 12, 2015 at 12:19

Thomas

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2 Comments

Thomas Over a year ago

Happy to help. Don't forget to mark the correct answer.

zygimantus Over a year ago

Should I use this syntax "data": or this one data:?

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