This is driving me mad, I have a JSON string that looks like so:
[["OX", "139.38"], ["LE", "131.28"], ["SA", "105.45"]]
I want to convert this to an array so that I can I can take advantage of indexOf:
alert(myArray.indexOf("LE"));
I've tried to convert my JSON string to an array using JSON.parse(myJSON) and jQuery.parseJSON(myJSON) but neither work.
How can I create an array from my JSON string? I'm happy to set up a loop just not sure how.
This works in chrome console:
var s = '[["OX", "139.38"], ["LE", "131.28"], ["SA", "105.45"]]';
var a = JSON.parse(s);
// a = [["OX", "139.38"],["LE", "131.28"],["SA", "105.45"]]
If you want to create a data structure to lookup the values by the keys:
var dict = {};
for (var i=0; i<a.length; i++){
dict[a[i][0]] = a[i][1];
}
Now dict looks like this:
//dict = {OX:"139.38", LE:"131.28", SA:"105.45"}
and we can index into it with the keys
dict['LE'] // = "131.28"
a[0].indexOf("OX") // => 0 -> The a[0] references the first Array within the overall array. Just FYI this is essentially what is called a multidimensional arrayThis will convert it like this [[""OX", "139.38"], ["LE", "131.28""]] -> ["OX", "LE"]
var newArr = [];
for(var i = 0; i < myArr.length; i++) {
newArr.push(myArr[i][0]);
}
This will convert it like this [[""OX", "139.38"], ["LE", "131.28""]] -> ["OX", "139.38", "LE", "131.28"]
var newArr = [];
for(var i = 0; i < myArr.length; i++) {
var tempArr = myArr[i];
for(var j = 0; j < tempArr.length; j++) {
newArr.push(tempArr[j]);
}
}
Now you can use indexOf.
If you want to get index at outter array:
var x = '[["OX", "139.38"], ["LE", "131.28"], ["SA", "105.45"]]';
var y = JSON.parse(x);
function getIndexByKey(key,array){
for(var i=0, len = array.length; i<len;i++){
if(array[i][0] === key){
return i;
}
}
}
function getIndexByVal(val,array){
for(var i=0, len = array.length; i<len;i++){
if(array[i][1] === val){
return i;
}
}
}
calling it:
getIndexByKey('OX', y); //0
getIndexByKey('LE', y); // 1
getIndexByKey('SA', y) // 2
getIndexByVal('139.38', y); //0
...
myArray[1].indexOf('LE');