I'm trying to print out only the odd indexed characters of an input string. I can't use string slicing but instead must use a loop. How it this done? Here is my code:
string = input("Please enter a string: ")
for each_char in string:
print("\n%s" % each_char)
You can use the enumerate function
>>> string = input("Please enter a string: ")
Please enter a string: helloworld
>>> for k,v in enumerate(string):
... if k%2==1:
... print(v) # No need \n as print automatically prints newline
...
e
l
w
r
d
direct string indexing will also work:
string = input("Please enter a string: ")
for i in range(1, len(string), 2):
print(string[i])
output:
Please enter a string: hello world
e
l
o
l
note the third (step) argument of range(start, stop[, step]).
and - yes - slicing would be much more elegant.
update: because you asked for it - here the version with slicing (you will find more information about slicing in the python tutorial):
for char in string[1::2]:
print(char)
range. That probably explains the dv. :-)