PHP: Define variables / array within a loop

Question

I've got this code

$vote = array(
    $arrayName[0][firstsector],
    $termin[1][firstsector],
    $termin[2][firstsector],
    $termin[3][firstsector]
);

Now I want to create a loop for it. I tried this:

$howMuchIneed = 5;

for ($x = 0; $x <= $howMuchIneed; $x++) {
    $vote = array(
        $arrayName[$x][firstsector]
    );
}

But the result doesn't look the same as the first code.

becuase you storing the value in $vote which is not an array — sandeep_kosta
– sandeep_kosta, Commented Oct 13, 2015 at 9:09

Lorenzo Belfanti · Accepted Answer · 2015-10-13 09:17:35Z

1

Have you tried this ?

for ($x = 0; $x <= $howMuchIneed; $x++) {
    array_push($vote, $arrayName[$x][firstsector]);
}

initializes Array

$vote = array();

answered Oct 13, 2015 at 9:12

Lorenzo Belfanti

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Comments

Kristian Vitozev · Accepted Answer · 2015-10-13 09:16:47Z

0

Try this (in your for loop):

$vote[] = $arrayName[$x]['firstsector'];

... and don't forget to declare your array before your loop!

$vote = array();

And in your first example you have 4 elements, condition in your for should be $x < 4 - arrays in PHP are zero-based.

answered Oct 13, 2015 at 9:10

Kristian Vitozev

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