Send a array with Jquery Ajax

Question

Trying to send an array from:

<select name='galaddvenn[]'  class='sel_add vl hidden' multiple='multiple'>
<option value='53'>name1</option>
<option value='352'>name2</option>
<option value='632'>name3</option>
<option value='543'>name4</option>..etc
</select>

...to/from Jquery with:

var ar = $("select#galaddvenn").serialize();

        j.ajax({
        data: ({ar : ar}), //tried with 'ar':ar
        dataType: "html",
        type:"post",
        url: "/ajax_gal_addvenn.php",
        cache: false,

....etc to PHP:

if(isset($_POST['ar'])){
$ar = mysql_real_escape_string($_POST['ar']);
var_dump($ar);

Gives me: bool(false) :(

What am i doing wrong here?

Nick Craver · Accepted Answer · 2010-09-12 20:52:12Z

3

.serialize() gets a complete POST string by itself, so it'll be formatted like this:

galaddvenn=53&galaddvenn=352&galaddvenn=632

So your call should look like this:

j.ajax({
    data: ar,
    dataType: "html",
    type:"post",
    url: "/ajax_gal_addvenn.php",
    cache: false
});

Then on the PHP side, you're looking for $_POST['galaddvenn'] instead.

You can test the output here.

answered Sep 12, 2010 at 20:52

Nick Craver

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Comments

jwueller · Accepted Answer · 2010-09-12 20:51:20Z

0

mysql_real_escape_string() expects a string. You cannot use it on your array. Check the docs for further information. You should use a loop to do this:

foreach ($_POST['ar'] as $key => $element) {
    $_POST['ar'][$key] = mysql_real_escape_string($element);
}

If you get errors like this, you should test your incoming data before manipulating them (e.g. use var_dump() before applying mysql_real_escape_string()).

answered Sep 12, 2010 at 20:51

jwueller

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2 Comments

Nick Craver Over a year ago

@Thundercat - It is essentially empty, or rather a useless string, see my answer :)

jwueller Over a year ago

@Thundercat: The reason is that you should look for $_POST['galaddvenn'] like suggested by Nick Craver. Use var_dump() on $_POST to see why ;)

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