Take the following string:
/foo/1/bar/2/cat/bob
I need to parse this into an object or array which ends up being:
foo = 1
bar = 2
cat = bob
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4 Answers
var sample = "/foo/1/bar/2/cat/bob".substring(1);
var finalObj = {};
var arr = sample.split('/');
for(var i=0;i<arr.length;i=i+2){
finalObj[arr[i]] = arr[i+1];
}
console.log(finalObj);1 Comment
David
Correct for question asked.
const str = '/foo/1/bar/2/cat/bob/test/'
const parts = str.split('/')
.filter(val => val !== '')
const obj = {}
for (let ii = 0; ii < parts.length; ii+=2) {
const key = parts[ii]
const value = parts[ii+1]
obj[key] = !isNaN(value) ? Number(value) : value
}
console.log(obj)
5 Comments
Rounin
Very elegant, @synthet1c.
Rajshekar Reddy
what happend to the initial
/ in the string ??David
Perfect. I decided to trim the initial / on the string to make this work.
garglblarg
Is there a reason for using
ii as an indexer or is that just something you prefer over the conventional i?
synthet1c
easier to search for with
ctrl + f you will probably have at least one i in your code, but ii is pretty much never used.Regular expressions is the tool of choice for all kinds of parsing:
str = '/foo/1/bar/2/cat/bob'
obj = {};
str.replace(/(\w+)\/(\w+)/g, (...m) => obj[m[1]] = m[2]);
console.log(obj);
2 Comments
A. Wolff
That's great but quite unreadable imho and i guess not that optimized. BUT that's just my opinion and you got my vote
Sebastian Simon
I’d use
([^\/]*) instead of (\w+). Empty key names and values are allowed and aren’t restricted to alphanumeric characters.Just for the fun of it,
let str = "/foo/1/bar/2/cat/bob",
arr = str.split("/"),
obj = {};
arr.shift();
while (arr.length) obj[arr.shift()] = arr.shift();
