How to match a string array with a string variable?

Question

I have an string array

$list = @("abc-1.0.1-xyz", "abc-1.0.2-xyz", "abc-1.0.3-xyz", "abc-1.0.4-xyz")

and a variable declared as $v = '1.0.2'.

Now I want to compare my array with the variable and get all the strings containing value greater than $v in another array.

For example: in this case abc-1.0.3-xyz and abc-1.0.4-xyz (greater than $v i.e. 1.0.2) will be added to another array.

Paweł Dyl · Accepted Answer · 2018-01-17 07:49:03Z

4

I would use simple regex:

$list = 'abc-1.0.1-xyz', 'abc-1.0.2-xyz', 'abc-1.0.3-xyz', 'abc-1.0.4-xyz'
$v = '1.0.2'
$list | % {
    $match = [regex]::Match($_, '\d+\.\d+\.\d+').Value
    if ($match -gt $v) { $_ }
}

Result

abc-1.0.3-xyz
abc-1.0.4-xyz

If you wish to use version comparison (string rules differs, i.e. 10<9), replace condition with following:

if ([version]$match -gt [version]$v) { $_ }

answered Jan 17, 2018 at 7:49

Paweł Dyl

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2 Comments

Smruti Chikali Over a year ago

Thank a ton. This worked. However, it is including abc-1.0.2-xyz in my new array for some reason. But i will trim it off.. No worries about it :)

Paweł Dyl Over a year ago

Replace last line with if ($match -gt $v) { $match }

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