assign value of multiple variable to form an array variable in php

Question

$pn=$_POST['pn'];
$ln=$_POST['ln'];
$logn=$_POST['logn'];
$wellno=$_POST['wellno'];  
for($i=0; $i<$chkcount; $i++) 
 {
  $msg=echo$wellno[$i].':'.echo$ln[$i].'/'.echo$pn[$i].'-'.echo$logn[$i];
  echo "<br>";
 }

I want $msg as a variable to send a message

Syscall · Accepted Answer · 2018-05-06 13:32:27Z

1

You cannot use echo to concatenate variables. echo returns nothing. Actually, you have a PHP Parse Error : "syntax error, unexpected 'echo'".

$pn=$_POST['pn'];
$ln=$_POST['ln'];
$logn=$_POST['logn'];
$wellno=$_POST['wellno'];  
for($i=0; $i<$chkcount; $i++) 
{
    $msg = $wellno[$i].':'.$ln[$i].'/'.$pn[$i].'-'.$logn[$i];
    do_something_with($msg);
}

If you want to make an array, you could use [] operator to push the value into the array:

$msg=[];
for($i=0; $i<$chkcount; $i++) 
{
    $msg[] = $wellno[$i].':'.$ln[$i].'/'.$pn[$i].'-'.$logn[$i];
}
print_r($msg);

answered May 6, 2018 at 13:32

Syscall

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