Algorithm, pseudo code

Question

I tried several times how to write a algorithm and a pseudo code for a program of finding the largest value among 3 user input integers? . I couldn't make it properly. Can i be helped?

@Alien i assumed that user inputs are x,y,z then if x>y then again checked the condition x>z if it is true, x is the largest. While x>y , z>y and then there is an anther condition if z>x then z is the largest number. Like wise i tried. It's hard to check conditions likewise. — Kavindu Gayantha
– Kavindu Gayantha, Commented Jul 31, 2018 at 5:31
Edit your question and add own pseudocode - seems you realize what to do but doubt in details. — MBo
– MBo, Commented Jul 31, 2018 at 8:48
Why do you think that finding the largest out of three integers is different than finding the largest out of, say, eleven integers? — ChatterOne
– ChatterOne, Commented Jul 31, 2018 at 9:01

mighty_dev · Accepted Answer · 2018-07-31 09:49:51Z

2

Pseudocode for maximum of 3 integers-

print max(max(first_integer,second_integer),third_integer)

answered Jul 31, 2018 at 9:49

mighty_dev

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5 Comments

Kavindu Gayantha Over a year ago

I think i didn't get this. Not clear enough to understand to me

mighty_dev Over a year ago

What was hard though?

Kavindu Gayantha Over a year ago

i didn't get what happens with this code. max(max(first_integer, second_integer), third_integer)

mighty_dev Over a year ago

max(a,b) finds maximum between a and b

Kavindu Gayantha Over a year ago

Aha. . I got it now. Thankz

Jim Mischel · Accepted Answer · 2018-07-31 18:37:43Z

So you have three numbers, x, y, and z. You want the largest one. So here are some rules:

If x > y, then the largest can't be y; it must be x or z. So check to see if x > z.
If x < y, then the largest can't be x; it must be y or z. So check to see if y > z.

That results in the code:

if (x > y)
    if (x > z)
        largest = x;
    else
        largest = z;
else // y >= x
    if (y > z)
        largest = y;
    else
        largest = z;

If you have a max function that returns the maximum of two numbers, then you can simplify that code:

largest = max(x, y);
largest = max(largest, z);

Which can further be optimized to largest = max(max(x, y), z);

Ok. Thankz. it has been explained well. i will try to think like this way.

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