Making a loop in python

Question

I have to make a program that when I enter a box_size number it show the box. They user should then be able to put in another number and repeat the process. Only when they type 0 should the program stop.

I've tried adding While True, if, and else statements and breaks but none of them stop the program from running.

#Input
box_size=input("box_size:" )
box_size=int(box_size)
for row in range(box_size):
  for col in range(box_size*2):
    print('*', end='')
  print()
print()

#Output
box_size:6
************
************
************
************
************
************

Barmar · Accepted Answer · 2019-06-18 01:26:40Z

2

Put while True: around the code. Then if the user enters 0, break out of the loop.

while True:
    box_size=input("box_size:" )
    box_size=int(box_size)
    if box_size == 0:
        break
    for row in range(box_size):
      for col in range(box_size*2):
        print('*', end='')
      print()
    print()

answered Jun 18, 2019 at 1:26

Barmar

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1 Comment

Technoob Over a year ago

Thank you! I've been struggling with this for hours.

YusufUMS · Accepted Answer · 2019-06-18 01:32:09Z

0

Try this simpler one. The box_size is initiated 1, then use it in the while loop. As long as the box_size is more than 0, the loop will always be executed.

box_size = 1
while box_size > 0:
    box_size = int(input("box_size:" ))
    for row in range(box_size):
        for col in range(box_size*2):
            print('*', end='')
        print()
    print()

answered Jun 18, 2019 at 1:32

YusufUMS

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