using regex with javascript and getting variables

Question

I've not used regex in a while and I'm trying to use it in Javascript

I have a url string like /something/a/a123 and I only want to match strings that begin with /something and be able to get a and a123 as variables without splitting the string into an array.

Is that possible?

const r = /something/[a-z][A-Z]*/[a-z0-9][a-z0-0]*/
const s = r.exec('/something/a/a123');

Ryszard Czech · Accepted Answer · 2020-06-10 14:33:07Z

1

Use

const r = /something\/([a-z]+)\/([a-z0-9]+)/i
const [_, a, b] = r.exec('/something/') || [,'','']
console.log(a, b)

Escape slashes and use round parens to capture those necessary regex parts.

edited Jun 10, 2020 at 14:33

answered Jun 10, 2020 at 14:19

Ryszard Czech

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5 Comments

Peter Seliger Over a year ago

... for the sake of not failing due to null es possible return value for exec you might consider changing your 2nd line to const [_, a, b] = r.exec('/something/a/a123') || [];

woopsie Over a year ago

how can I exclude a particular word? eg. I want /something/a/a123 but I don't want /something/a/specificNonAlphaWord

Ryszard Czech Over a year ago

@woopsie /something\/([a-z]+)\/(?!word)([a-z0-9]+)/i

woopsie Over a year ago

is there a way to make it ONLY accept alphanums wihtout having to use (?!word)? \/([a-z0-9]+) something here to make sure it's only alpha? /i

Ryszard Czech Over a year ago

@woopsie /something\/([a-z]+)\/((?:[a-z]+\d|\d+[a-z])[\da-z]*)/i might do.

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