schema_dir=schema_app
for SCHEMA_CHANGE in $schema_dir/*
do
so my pwd is /A/B/C/scripts
within which I have subdirectories (schema_app, schema_data, etc).
I want a for loop to run through the files in each directory, depending upon the parameter I pass to the script initially.
What mistake am I doing here ?
Because, when I echo SCHEMA_CHANGE (the file name), it is showing like this schema_app/filename.
how can I get only the filename here ?
You aren't doing anything wrong. schema_app/filename is the correct path to the file. It's what you need to pass to a command (or a redirection) to work on the file. Using filename alone wouldn't work: how would the command know in what directory the file is?
If for some reason you need the filename without its directory part, you can use
"${SCHEMA_CHANGE##*/}"
This takes the value of the variable SCHEMA_CHANGE and removes the part up to and including the last / (or leaves the value unchanged if there's no /), so you get the filename without its directory part.
SCHEMA_CHANGE and removes the part up to and including the last / (removes the longest prefix matching */).
printf %s\\n "${SCHEMA_CHANGE#*_*/}"