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I have script here that will list the date that the user will enter and output the date 5 days ago.

#!/bin/bash
echo "What month?"
            echo "1 - January"
            echo "2 - February"
            echo "3 - March"
            echo "4 - April"
            echo "5 - May"
            echo "6 - June"
            echo "7 - July"
            echo "8 - August"
            echo "9 - September"
            echo "10 - October"
            echo "11 - November"
            echo "12 - December"
            echo ""
            echo -n "What month?  "
            read m

            if [ "$m" == "1" ]
            then
            mn="Jan "
            elif [ "$m" == "2" ]
            then
            mn="Feb "
            elif [ "$m" == "3" ]
            then
            mn="Mar "
            elif [ "$m" == "4" ]
            then
            mn="Apr "
            elif [ "$m" == "5" ]
            then
            mn="May "
            elif [ "$m" == "6" ]
            then
            mn="Jun "
            elif [ "$m" == "7" ]
            then
            mn="Jul "
            elif [ "$m" == "8" ]
            then
            mn="Aug "
            elif [ "$m" == "9" ]
            then
            mn="Sep "
            elif [ "$m" == "10" ]
            then
            mn="Oct "
            elif [ "$m" == "11" ]
            then
            mn="Nov "
            elif [ "$m" == "12" ]
            then
            mn="Dec "
            else
            echo "Invalid month"
            fi
            echo ""

            #DAY
            echo -n "What day? "
            read d
            if [ "$d" -lt "9" ]
            then
                    mnd="$mn"" ""$d"
            elif [ "$d"  -gt "31" ]
            then
                    mnd="1"
            else
                    mnd="$mn""$d"
            fi



 for dy in {0..4}; do
    date -d "$mn $d - $dy days" +'%b %_d'
 done

Output:

What month?
8
What day?
1

Aug  1
Jul 31
Jul 30
Jul 29
Jul 28

What I want now is to store each date in to variable for example the first line must Aug 1 must be stored on variable x1 Jul 31 must be stored on variable x2 etc.. What I mean whatever output on the first list must be stored on x1 and so on.

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1 Answer 1

Reset to default
2

Use an array instead of trying to create separate variables.

declare -a x

for dy in {0..4}; do
  x+=( "$( date -d "$mn $d - $dy days" +'%b %_d' )" )
done

You may then access the four values in ${x[0]} through to ${x[3]}.

For the first part of your script, have you considered using a select statement?

select mn in "Jan" "Feb" "Mar" "Apr" "May" "Jun" \
             "Jul" "Aug" "Sep" "Oct" "Nov" "Dec"
do
  if [[ -z "$mn" ]]; then
    echo "Invalid choice" >&2
  else
    break
  fi
done

printf "You selected '%s'\n" "$mn"

This does the following:

1) Jan    3) Mar   5) May   7) Jul   9) Sep  11) Nov
2) Feb    4) Apr   6) Jun   8) Aug  10) Oct  12) Dec
#? 56
Invalid choice
#? 5
You selected 'May'

The value of $mn will be the selected string (May for example).

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8
  • Will this actually I'm looking for. I can't explain more further earlier the i++ hahaha. Commented Aug 5, 2016 at 6:54
  • for the first part of my script I already have that if..else statement is under of select statement Commented Aug 5, 2016 at 6:57
  • how can the variable? is right? echo ${x[0]} ? Commented Aug 5, 2016 at 7:03
  • @JJ-SAMA echo "${x[0]}" outputs the first value in the array x. The select statement replaces your if ... then ... else statements. Commented Aug 5, 2016 at 7:07
  • 1
    @JJ-SAMA Sorry, I made a typo. It's fixed now. Commented Aug 5, 2016 at 7:14

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