The correct way to calculate MIPs of a function on a microcontroller [closed]

Question

I want to calculate MIPs of a function on a microcontroller. Here is how I do it.
1. keil setting. Use Simulator and Xtal = 25MHz

2. Run simulator in debug mode.
   As you can see, it takes 200ms to run fun() once.
   200ms(0.2s) * 25MHz = 5M. Does it mean that running fun() takes 5MIPs?
   One thing to note that the MIPs of fun() is independent of platform or crystal's oscillation frequency.
   Thank you.

Answer 1

As you may know, MIPS means Mega Instructions Per Second. So the formula would be

CHIP_MIPS = number_of_mega_instructions / number_of_seconds.

If your chip is running at 25 MHz, it means that it performs 25 mega instructions per seconds, so knowing the number of seconds and the CHIP_MIPS, the formula would be

number_of_seconds * CHIP_MIPS = number_of_mega_instructions

So fun needs 5 Mega Intructions