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I apologise for the simple question, but I've trying to learn to write my code in a more idiomatic way, after having learned Mathematica mostly through trial and error for a long time.

Say I have two lists

l1={x,y,z}
l2={a,b,c}

And I want to create a replacement rule

{x->a,y->b,z->c}

I can achieve this through

Table[l1[[i]] -> l2[[i]], {i, 1, Length[l1]}]

But this feels cumbersome and I was wondering if there's a cleaner, more idiomatic way of making the same replacement rule?

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    $\begingroup$ Take a look at Thread / AssociationThread. $\endgroup$ Commented Jun 5, 2019 at 19:30

2 Answers 2

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Thread[ l1 -> l2]

Should do the trick.

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As usual, in Mathematica, there are several ways to do it.

Rule@@@Transpose@{l1, l2}

is one way although

Thread@Rule[l1, l2]

is probably more direct.

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