This is an example to make Pi in 3D dimension
Thanks @xzczd for providing the fast version. Link Smoothing the Region?
r = RegionProduct[#, Line[{{0.}, {10.}}]] &@
ImageMesh@ColorNegate@ImageResize[Rasterize[" \[Pi]"], 100];
r2 = TransformedRegion[r, TranslationTransform[-RegionCentroid@r]];
r3 = RegionUnion@
Table[TransformedRegion[RepairMesh@r2,
RotationTransform[i, {0, 1, 0}]], {i, -Pi/6, Pi/6, Pi/75}];
cy = DiscretizeRegion@Ball[{0, 0, 0}, 15];
RegionIntersection[r3, cy]
The visualization failed, but RegionEmbeddingDimension shows the dimensions are same.
RegionIntersectionsays:RegionIntersectionis defined only for regions with the sameRegionEmbeddingDimension:
{RegionDimension /@ {r3, cy}, RegionEmbeddingDimension /@ {r3, cy}}
(* Yes, Different dimension {{2, 3}, {3, 3}} *)
Also failed by repairing the mesh
cyrepair = RepairMesh@cy;
RegionIntersection[r3, cyrepair]
(* Not worked *)
{RegionDimension /@ {r3, cyrepair}, RegionEmbeddingDimension /@ {r3, cyrepair}}
(* {{2, 2}, {3, 3}} *)
However, the code works if all dimension of regions are same.
{RegionDimension /@ {r2, cy}, RegionEmbeddingDimension /@ {r2, cy}}
RegionIntersection[r2, cy]
(* {{3, 3}, {3, 3}} *)


