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Questions tagged [factorization]

Questions on factoring various types of mathematical expressions, with the use of Factor, FactorInteger, FactorSquareFree and related commands.

4 votes
1 answer
239 views

The responses to my previous question "Are there any tips/tricks to improve simplification..." were very helpful, but as I move forward in the same personal project mentioned in that ...
Lawton's user avatar
  • 287
9 votes
3 answers
391 views

I've been using Wolfram Engine 14.3 for a personal project, and a common problem I've encountered is that its outputs — even after using Simplify[], ...
Lawton's user avatar
  • 287
2 votes
1 answer
88 views

The documentation of Modulus suggests that the value of this option should be an explicit number (or Automatic). However, ...
user688486's user avatar
2 votes
1 answer
162 views

I want to transform expr by factoring out only the E^(-t γ) term. I could implement it like in my code below, but is there a ...
Soon's user avatar
  • 1,590
3 votes
1 answer
238 views

Here are two examples with ordinary extensions: Factor[1 + x^4, Extension -> Sqrt[2]] Factor[x^2 + 2 Sqrt[3] x + 3, Extension -> Automatic] But what about &...
azerbajdzan's user avatar
  • 35.1k
0 votes
0 answers
56 views

Factor[8 x^2 - 73 y^2] returns 8 x^2 - 73 y^2 How do I go about factoring it into (8^.5 x + 73^.5 y)*(8^.5 x - 73^.5 y) ?
Anton's user avatar
  • 2,072
1 vote
0 answers
160 views

I was solving a RSA factorization problem with a weak prime. In a given base, the prime was made of a lots of zeroes and can be factorized pretty quickly. See this write-up. I checked the code for ...
Crypto's user avatar
  • 382
2 votes
3 answers
219 views

Not sure how to do this with Factor/Collect etc. I'm thinking this might not be straightforward at all. Given a large Laurent polynomial I am trying to factor it into irreducible Laurent polynomials. ...
ngc5139's user avatar
  • 441
3 votes
2 answers
195 views

Consider this simple 5th order polynomial: pol=x^5+x^4+1 Factor[pol] (* (1+x+x^2)(1-x+x^3) *) root=FindInstance[pol==0, x] (* -1/2 -I/2 Sqrt[3] *) ...
Jos Bergervoet's user avatar
5 votes
3 answers
452 views

The real analytical solution of the algebraic equation $x^5 + 10 x^3 + 20 x == 4$ is $x=-2^{2/5} + 2^{3/5}$, how to get it with Mathematica? I've tried with ...
Soriak's user avatar
  • 433
3 votes
2 answers
381 views

It seems Mathematica likes to factor some things in less than optimal ways. For example, for the oscillating exponential function (F) below, is there any way to force it to reduce both the number of ...
ChaSta's user avatar
  • 1,197
2 votes
3 answers
154 views

Consider the following simple polynomial in two variables 5 + 2x + 2y. Suppose I want to simplify it to 5+2(x+y). I have no idea ...
user1620696's user avatar
0 votes
1 answer
74 views

I what to factor a polynomial with complicated symbolic coefficients Factor[p0^2 + k^2 r^2 \[Tau]^2 - 2 k p0 r \[Tau]^2 \[Omega] + p0^2 \[Tau]^2 \[Omega]^2] In ...
Haiqin Tang's user avatar
0 votes
2 answers
100 views

I have a large term (a small snippet of which is below as an example) that I am aiming to prove is positive. I know that all the involved values are probabilities and in particular, they lie in (0, 1)....
Andrew Ferdowsian's user avatar

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