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Questions tagged [diophantine-equations]

Diophantine equations are polynomial equations $F=0$, or systems of polynomial equations $F_1=\ldots=F_k=0$, where $F,F_1,\ldots,F_k$ are polynomials in either $\mathbb{Z}[X_1,\ldots,X_n]$ of $\mathbb{Q}[X_1,\ldots,X_n]$ of which it is asked to find solutions over $\mathbb{Z}$ or $\mathbb{Q}$. Topics: Pell equations, quadratic forms, elliptic curves, abelian varieties, hyperelliptic curves, Thue equations, normic forms, K3 surfaces ...

14 votes
2 answers
790 views

Before Andrew Wiles's 1997 proof of Fermat's Last Theorem, in 1985, Étienne Fouvry et al. proved that the first case of FLT holds for infinitely many primes $p$. Is there any infinite class of primes ...
Euro Vidal Sampaio's user avatar
-6 votes
0 answers
97 views

I am an independent researcher. This arose in the context of studying the Beal conjecture. Setup: Factor $A^3+B^3=(A+B)(A^2-AB+B^2)=C^n$. For coprime $A,B$: $\gcd(A+B, A^2-AB+B^2)$ divides $3$. This ...
Nick Jeffers's user avatar
0 votes
0 answers
165 views

Consider this equation \begin{equation} y^2 = x^3 + (36n + 27)^2 \cdot x^2 + (15552 n^3 + 34992 n^2 + 26244 n + 6561) \cdot x + (46656 n^4 + 139968 n^3 + 157464 n^2 + 78713 n + 14748) \end{equation} ...
Agbanwa Jamal's user avatar
1 vote
0 answers
131 views

By Størmer's theorem, for every fixed $k$, there are only finitely many $n$ such that the set of prime divisors of $n(n+1)$ is a subset of the first $k$ primes. The OEIS sequence A141399 tracks those $...
Euro Vidal Sampaio's user avatar
4 votes
1 answer
237 views

Starting from a math problem involving a square and a unit circle, I used some elementary algebraic transformations and discovered that for any arbitrary $u, v$, if we define $a, b, c$ as follows: $$a ...
Đào Thanh Oai's user avatar
12 votes
0 answers
389 views

As it is clear from the title, the question is whether there exist integers $x,y,z$ such that $$ y^2z+z^2y = x^3+x^2+3x-1. $$ My two-years-old notes claim that I checked it up to $|x|\leq 450,000,000$ ...
Bogdan Grechuk's user avatar
5 votes
1 answer
184 views

Let $f(n)$ be an integer function such that $$ f(n) = \sum\limits_{i=1}^{n} \sum\limits_{j=1}^{i} \sum\limits_{k=1}^{j} [(3ijk - (ij + ik + jk)) = n]. $$ Here square bracket denotes Iverson bracket. I ...
user avatar
15 votes
0 answers
638 views

Do there exist integers $x,y,z$ satisfying $$ (3x-1)y^2 + x z^2 = x^3-2 \quad ? $$ Hilbert's 10th Problem is unsolvable in general, but is still open for cubic equations: it is unknown whether there ...
Bogdan Grechuk's user avatar
1 vote
0 answers
344 views
+50

Let $h(n)$ be the function that returns the minimum exponent in the prime factorization of $n$. We adopt the convention $h(1) = \infty$, so $1/h(1) = 0$. According to the abc conjecture, there should ...
Đào Thanh Oai's user avatar
3 votes
1 answer
356 views

How to find new parametric forms for the OP diophantine equation $$A^4+28A^3B+70A^2B^2+28AB^3+B^4=C^4+28C^3D+70C^2D^2+28CD^3+D^4$$ The smallest parametric solution can be found in this collection by ...
Aleksandr 's user avatar
2 votes
1 answer
290 views

Let $a,b,c$ be coprime positive integers with $a+b=c$. For $n=\prod p_i^{e_i}$, define $S_n=\frac{1}{\omega(n)}\sum_{i=1}^{\omega(n)}\frac{1}{e_i}.$ where $\omega(n)$ is the number of distinct prime ...
Đào Thanh Oai's user avatar
12 votes
5 answers
749 views

I am trying to find parametric families of rational solutions $(r, s, t) \in \mathbb{Q}^3$ for the Diophantine equation: $$ (r^2 + s^2)(r^2 s^2 + 1) = t^2 $$ I consider the following solutions to be ...
Randall's user avatar
  • 121
3 votes
0 answers
87 views

Fermat two squares theorem has a well known proof due to Heath Brown that uses involutions, that is, linear operators that are equal to their own inverses. This allows so called one sentence proofs, ...
Euro Vidal Sampaio's user avatar
7 votes
0 answers
621 views

Are there infinitely many primitive solutions to the equation $x+y=z$ where $x,y,z$ are all prime powers? This follows from the infinitude of prime gaps of size not exceeding 4, but I wonder If other ...
Euro Vidal Sampaio's user avatar
3 votes
0 answers
98 views

Consider the Pell-type equation $ax^2 - by^2 = c$. When $c = \pm 1$, the following Stormer-type result turns out to hold (see e.g. Theorem 3.2): Theorem. Let $a,b$ be coprime positive integers whose ...
DesmondMiles's user avatar

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