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Questions tagged [infinite-combinatorics]

Combinatorial properties of infinite sets. This is a corner-point of set theory and combinatorics.

9 votes
2 answers
153 views

Let's take an $X \subset 2^\omega$ such that for any two distinct ultrafilters on $\omega$ there is a set $A \in X$ such that $A$ is in one ultrafilter but not the other. Can $X$ have cardinality less ...
violeta's user avatar
  • 695
10 votes
1 answer
352 views

Let $J\subseteq {\cal P}(\omega)$ be the collection of infinite subsets whose complement is also infinite. Is there a fixed-point free bijection $\varphi:J\to J$ such that $\varphi(j)\subseteq j$ for ...
Dominic van der Zypen's user avatar
3 votes
0 answers
59 views

Jung and Niemeyer define an equivalence relation on the set of rays of an infinite graph where $T_p(X)$ is the set of vertices at a distance less or equal than $p$ from some vertex at $X$. (distance ...
violeta's user avatar
  • 695
12 votes
0 answers
296 views

In the last few years, graph theorists have taken Seymour/Robertson's notion of a tangle and generalized it to an abstract version based on the definition of a 'separation system' - a set with a ...
violeta's user avatar
  • 695
11 votes
1 answer
322 views

The starting point of this question is bof's classification in this comment of indecomposable ordinals. In particular, every complete well-ordering on more than $1$ point is decomposable. Also, the ...
Dominic van der Zypen's user avatar
13 votes
0 answers
768 views

Let $X$ be a non-empty set. We say that a relation $R \subseteq (X \times X)$ is shrinkable to $A \subseteq X$ if there is an injection $f:X \to A$ with $(x, y) \in R$ if and only if $(f(x), f(y)) \in ...
Dominic van der Zypen's user avatar
8 votes
3 answers
919 views

Is there a map $s: \mathbb{Q}\times\mathbb{Q} \to \mathbb{N}$ with the following properties? For all $z\in\mathbb{Z}$, the restriction $s|_{[z,z+1)\times [z,z+1)}: [z,z+1)\times [z,z+1) \to \mathbb{N}...
Dominic van der Zypen's user avatar
15 votes
0 answers
385 views

This is a follow-up question to a very old one of mine, which was actually answered in a 1991 paper of Scheepers. Let $[X]^\omega$ denote the family of all countable subsets of $X$. Suppose $\{ f_x : ...
Monroe Eskew's user avatar
  • 21.4k
1 vote
1 answer
82 views

We endow $\newcommand{\Po}{{\mathcal P}(\omega)}\Po$ with a graph structure by letting $E = \big\{\{a,b\}: a, b\subseteq \omega \land a \neq b \land (\exists n\in \omega(a\cap b = \{n\})\big\}$. Every ...
Dominic van der Zypen's user avatar
-2 votes
1 answer
141 views

If $\newcommand{\Z}{\mathbb{Z}}\newcommand{\N}{\mathbb{N}}f:\Z\times\Z \to \N$ we let $${\rm I}(f)=\{n\in\N : f^{-1}(\{n\}) \text{ is infinite}\}$$ be the set of natural numbers with infinite pre-...
Dominic van der Zypen's user avatar
3 votes
0 answers
129 views

Inspired by Dominic van der Zypen's question and Ilya Bogdanov's answer I wonder what to make of two cardinal characteristics. To define them, let $e_U$ be the increasing enumeration of an infinite ...
TLo's user avatar
  • 1,172
13 votes
1 answer
540 views

For the set $\omega$ of non-negative integers, we let $\newcommand{\oo}{[\omega]^\omega}\oo$ be the collection of infinite subsets of $\omega$. If $U\in \oo$, there is a unique order-preserving ...
Dominic van der Zypen's user avatar
17 votes
1 answer
564 views

Noam Elkies maintains a page of mathematical miscellany on his website. The last entry on this page is a problem he proposed to the American Mathematical Monthly, rejected on the advice of both ...
Will Brian's user avatar
  • 20.3k
5 votes
3 answers
496 views

Suppose $\kappa$, $\lambda$, $\mu$, and $\nu$ are cardinals which may or may not be ordinals. Can we prove without resorting to the axiom of choice either of the following: $\kappa + \lambda \...
TLo's user avatar
  • 1,172
3 votes
1 answer
119 views

We say that a hypergraph $H=(V,E)$ is $T_2$ if for all $v, w\in V$ with $v\neq w$, there are disjoint sets $e_1, e_2\in E$ with $v\in e_1, w\in e_2$. For $v\in V$, let $e_v= \{e\in E: v\in e\}$. Given ...
Dominic van der Zypen's user avatar

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