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Questions tagged [set-theory]

forcing, large cardinals, descriptive set theory, infinite combinatorics, cardinal characteristics, forcing axioms, ultrapowers, measures, reflection, pcf theory, models of set theory, axioms of set theory, independence, axiom of choice, continuum hypothesis, determinacy, Borel equivalence relations, Boolean-valued models, embeddings, orders, relations, transfinite recursion, set theory as a foundation of mathematics, the philosophy of set theory.

4 votes
1 answer
250 views

The counting measure on $\mathbb{R}^n$ is a map that takes a subset $A$ of $\mathbb{R}^n$ and returns its cardinality if it is finite or the symbol $\infty$ if it is infinite. So, if $A\subseteq\...
Cosine's user avatar
  • 1,038
-11 votes
0 answers
147 views

I encountered this mathematical structure but need help decoding the notation: [ T = \prod_{i=1}^{\infty} \mathbb{N} ] with hierarchy levels: $!1, !2, !3\ldots$ $T1G, T1H, T1B\ldots$ $A1, A2, A3\...
tea no's user avatar
  • 1
1 vote
1 answer
193 views

Let ${}^\omega\omega$ denote the set of functions $f:\omega\to \omega$. For $f, g \in {}^\omega\omega$ we define $f\leq^* g$ if there is $N\in\omega$ such that $f(n)\leq g(n)$ for all $n\in \omega$ ...
Dominic van der Zypen's user avatar
4 votes
1 answer
318 views

For $n\in\omega$ and $x$ a real let $C_n^x$ be the canonical $\Pi^1_n(x)$-complete set. E.g. $C_1^x=\mathcal{O}^x$, etc. I recall seeing long ago the fact that, assuming large cardinals (precisely: ...
Noah Schweber's user avatar
4 votes
0 answers
115 views

It's well known (and not so hard to prove directly) that for any topological space $X$ the group $C^b(X, \mathbb Z)$ — locally constant functions taking only finitely many values — is a free abelian ...
Denis T's user avatar
  • 5,926
0 votes
0 answers
164 views

I am reading Kunen's books on set theory and logic. In his approach, the metatheory is finitistic (which can be approximated in PRA). This implies that in the finitistic metatheory, one can do formal ...
Link L's user avatar
  • 225
15 votes
1 answer
679 views

This mathematical game occurred to me. It may be quite basic for experts, but it seems to lead to some interesting questions. Turns are indexed by elements of $\mathbb{N} = \{1,2,\ldots, \}$. In turn $...
Mark Wildon's user avatar
  • 11.9k
2 votes
0 answers
139 views

I am trying to get myself familiar with normalization of iteration trees, and one technical concept which I find especially hard to parse is inflation. I am following the notation of Farmer ...
Raczel Chowinski's user avatar
15 votes
1 answer
727 views

Working in $ZFC$, the statement "$0^\sharp$ exists" is often liberally taken to be one of many known equivalent statements. However, working in $Z_2$ or $ZFC^-$ (with collection, well-...
user116499's user avatar
8 votes
1 answer
347 views

It seems that Jensen's proof of the consistency of CH + SH used class forcing, but the revelant properties are not clearly verified. I haven't learnt about class forcing, so I wonder whether it is ...
Ning Gan's user avatar
7 votes
1 answer
290 views

For a regular cardinal $\kappa$, a $\kappa$ tree $T$ is called special when there is a regressive function $f : T \to T$ (regressive in the tree order) so that the inverse image of every point is the ...
Monroe Eskew's user avatar
1 vote
0 answers
168 views

This is a follow-up to this recent question. We were reminded that the partition principle is the statement that for every surjection $f : A \longrightarrow B$ there is an injection $g : B \...
TLo's user avatar
  • 1,172
6 votes
1 answer
182 views

In Friedman and Magidor - The Number of Normal Measures, the authors use a nonstationary support iteration of posets, rather than the more customary countable or Easton support iterations: conditions $...
Jayde SM's user avatar
  • 2,215
9 votes
0 answers
122 views

There are two notions of n-ineffable. One is standard, defined in Baumgartner's paper, used by Harvey Friedman: κ is n-ineffable iff for every 2-coloring of $[\kappa]^{n+1}$, there is a stationary ...
Reflecting_Ordinal's user avatar
9 votes
1 answer
231 views

It is known that for $n\ge 1$, $\mathbf{\Delta}^1_{2n}$-Determinacy implies $\mathbf{\Pi}^1_{2n}$-determinacy, but as far as I know, this is a theorem in $\mathsf{ZFC}$. It brings the following first ...
Hanul Jeon's user avatar
  • 3,426

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