I have two arrays
var a= $("#update-select1").val(); // gives value 1,2,4
var b= $("#update-select2").val(); // 1,2,5
I want two different arrays from the above two arrays.
//array has the values which is in `b` but not in `a`
var c = [5]
//another array has value in `a` but not in `b`
var d =[4]
You can use Array.filter this way:
var c = [1,2,5]
.filter(function(a){return this.indexOf(a) === -1},[1,2,4]); //=> [5]
var d = [1,2,4]
.filter(function(a){return this.indexOf(a) === -1},[1,2,5]); //=> [4]
Or:
function notIn(a){
return this.indexOf(a) === -1;
}
var a = [1,2,4]
,b = [1,2,5]
,c = b.filter(notIn,a)
,d = a.filter(notIn,b);
indexOf, see developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…You can try the grep() method
var a1 = [1, 2, 4];
var a2 = [1, 2, 5];
var difference = $.grep(a1, function (x) {
return $.inArray(x, a2) < 0
});
alert(" the difference is " + difference);
I know this is an old question, but I thought I would share this little trick.
var diff = $(old_array).not(new_array).get();
diff now contains what was in old_array that is not in new_array
Found this on Compare 2 arrays which returns difference
try something like this
var a= [1,2,4];
var b= [1,2,5];
var c = [];
jQuery.each(b,function(k,v){
if(a.indexOf(v) < 0){
c.push(v);
}
})
console.log(c);//[5]
var d = [];
jQuery.each(a,function(k,v){
if(b.indexOf(v) < 0){
d.push(v);
}
})
console.log(d);//[4]
concat(), but who knows ?val()doesn't even return arrays ?val()returns array. I was thinking the same...