Is it possible in Java to make an array in a style similar to this, i have been searching for a while and haven't found anything.
int[] foo = {
for(String arg:args)
return Integer.parseInt(arg);
};
Add a comment
|
6 Answers
No, but you can do this instead :
int[] foo = new int[args.length];
for(int i = 0; i < foo.length; i++) {
foo[i] = Integer.parseInt(args[i]);
}
3 Comments
Apurva
I wrote the same answer. Sorry I didn't know you already posted it. Maybe I was writing that time.
Eran
@Clutchy You're welcome (and it seems like you just got enough rep to vote :))
Clutchy
I was learning Python before and everything seems so long for me in Java :P
Not exactly, but try this.
int[] foo = new int[args.length]; //Allocate the memory for foo first.
for (int i = 0; i < args.length; ++i)
foo[i] = Integer.parseInt(args[i]);
//One by one parse each element of the array.
Comments
With Java 8, it can be done like this:
int[] foo = Stream.of(args).mapToInt(str -> Integer.parseInt(str)).toArray();
Comments
Kind of... Since Java 8 we have streams which can simulate loop and allow us to do things like
int[] arr = Arrays.stream(args).mapToInt(s -> Integer.parseInt(s)).toArray();
or its equivalent using method references
int[] arr = Arrays.stream(args).mapToInt(Integer::parseInt).toArray();
Comments
With array no, but you can do something similar with List:
final String args[] = {"123", "456", "789"};
List<Integer> list = new LinkedList<Integer>(){
{
for (String arg: args){
add(Integer.parseInt(arg));
}
}
};
System.out.println(list); // [123, 456, 789]
With array you have to do the following:
int[] foo = new int[args.length];
for (int i = 0; i < foo.length; i ++) {
foo[i] = Integer.parseInt(args[i]);
}
