PHP: echo item from array by its value instead of by its array index

Question

I have an array with two values stored for each item, the first one called "ID" and the second one called "en". The ID values are unique integers and the en values are text.

Now I would like to echo a specific item from the array referring to it by its ID.

I tried the below but this goes by the index within the array so it gives me a different item than what I need.

Can someone tell me how I can echo e.g. the item with ID = 10 instead of the item with the array index = 10 (here it currently gives me Value11 instead of Value1) ?

My PHP:

<?php echo $arr[10]["en"]; ?>

The array:

Array ( 
        [0] => Array ([ID] => 10 [en] => Value1 ),
        [1] => Array ([ID] => 11 [en] => Value2 ),
        [2] => Array ([ID] => 12 [en] => Value3 ),
        // ...
        [10] => Array ([ID] => 20 [en] => Value11 ),
        // ...
      )

Many thanks in advance, Mike

Thanks - this is just an example. This changes all the time which is why I want to go by my own ID since this stays the same. — keewee279
– keewee279, Commented Jun 15, 2015 at 18:40

Death-is-the-real-truth · Accepted Answer · 2015-06-15 18:58:48Z

2

I think you want that when you pass any value it will check that where the value exist at id index of your multidimensional array and give it's key and it's en index value.

<?php

$array = Array ( 
        '0' => Array ('ID' => 10, 'en' => 'Value1' ),
        '1' => Array ('ID' => 11, 'en' => 'Value2' ),
        '2' => Array ('ID' => 12, 'en' => 'Value3' )
        );
function findKeyandValue($array,$value){

   foreach($array as $key=>$val){
    if($val['ID']== $value){
        echo 'key of the value pass='.$key.'and its en value is'.$val['en'].'<br>';
    }
}

}

findKeyandValue($array,10);
?>

Output:- https://eval.in/382010

answered Jun 15, 2015 at 18:58

Death-is-the-real-truth

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5 Comments

keewee279 Over a year ago

Thanks a lot for this as well ! This is great and works well but it seems to be very similar to the answer from splash58. Am I missing something here ?

Death-is-the-real-truth Over a year ago

iIt returns the key of given value and also the en value also.

keewee279 Over a year ago

Thanks for that ! This is very helpful but in this case I just need the en value. :)

Death-is-the-real-truth Over a year ago

it's simple remove $key from echo. and instead of echo put return

keewee279 Over a year ago

For some reason I couldn't get the other solution to work fully, perhaps due to the two dimensions in the array or I made a mistake as it always returned nothing but it worked with your suggestion so I accepted that one and voted splash's comments up. Thanks again !

splash58 · Accepted Answer · 2015-06-15 18:58:54Z

2

function FindByID($arr, $id) {
  foreach($arr as $item) {
   if ($item['ID'] === $id) return $item['en'];
  } 
  return null;
}

echo FindByID($arr, 11);

edited Jun 15, 2015 at 18:58

answered Jun 15, 2015 at 18:47

splash58

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14 Comments

splash58 Over a year ago

@jQuery.PHP.Magento.com you make my code invalid with your else. You may try. Return null must be after foreach

Pratik Joshi Over a year ago

Then pls add { after foreach and after end of foreach. Else it makes your code confusing.

splash58 Over a year ago

@jQuery.PHP.Magento.com Strange practice to vote against the program to work

splash58 Over a year ago

1) id is argument of function. You may use any variable or constant $a = 10; FindByID($arr, $a);

splash58 Over a year ago

2) the same about array - write the name of array you use. It is it does not matter - the different or the same name

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