Adding numbers in shell scripting [duplicate]

Question

Just started doing basic shell scripting need some help with adding number for example 6 9 -4 2 with add command

#!/bin/bash


function add() {
sum=`expr $a + $b + $c + $d`
echo "$sum";  }

read a b c d
add

fi

So whats wrong with the code? Can anyone show me the code with a for loop? please. — gandhifolie
– gandhifolie, Commented Aug 12, 2015 at 2:48
does your example data include fractions? Do you mean 1/2, or .5 ? Read about awk it can help you do these transparently without worry about floating point or integer. echo '6 9 -4 2 ' | awk '{print tot=$1+$2+$3+$4+0.0}' (remove the +0.0 if you need integer addition). Good luck. (misread your comment about fractions, sorry). Good luck again ;-) — shellter
– shellter, Commented Aug 12, 2015 at 3:35

user1934428 · Accepted Answer · 2015-08-12 05:48:20Z

3

Aside of the "fi" at the end of your script (likely a copy-and-paste error?), the script looks correct, although it can be done easier: bash already has the capability to do calculation, so you don't need to create a child process by invoking expr:

echo $((a+b+c+d))

would also output the sum.

answered Aug 12, 2015 at 5:48

user1934428

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