Retrive array object from object in Javascript

Question

var obj={"firstName":"John","lastName":"Smith","isAlive":true,"age":25,"address":{"streetAddress":"21 2nd Street","city":"New York","state":"NY","postalCode":"10021-3100"},"phoneNumbers":[{"type":"home","number":"212 555-1234"},{"type":"office","number":"646 555-4567"},{"type":"mobile","number":"123 456-7890"}],"children":[],"spouse":null};

I want to access the phoneNumbers field So I use

phone=obj.phoneNumbers;

I get an array but without "phoneNumbers" field.I want to get someting like this:

{
  "phoneNumbers": [
    {
      "type": "home",
      "number": "212 555-1234"
    },
    {
      "type": "office",
      "number": "646 555-4567"
    },
    {
      "type": "mobile",
      "number": "123 456-7890"
    }
  ]
}

and why should this be useful?

Jonas Wilms
– Jonas Wilms

2017-05-31 16:56:41 +00:00
Commented May 31, 2017 at 16:56 — Jonas Wilms
– Jonas Wilms, Commented May 31, 2017 at 16:56
because my API ask for it

YAKOVM
– YAKOVM

2017-05-31 16:59:59 +00:00
Commented May 31, 2017 at 16:59 — YAKOVM
– YAKOVM, Commented May 31, 2017 at 16:59
@Yakov You can check my answer.

Umair
– Umair

2017-05-31 17:01:47 +00:00
Commented May 31, 2017 at 17:01 — Umair
– Umair, Commented May 31, 2017 at 17:01

Quartal · Accepted Answer · 2017-05-31 16:54:04Z

3

You have to create a new object then

var phone = { "phoneNumbers": obj.phoneNumbers };

answered May 31, 2017 at 16:54

Quartal

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Comments

James · Accepted Answer · 2017-05-31 16:53:23Z

3

You can add that part in:

var phone = {"phoneNumbers" : obj.phoneNumbers};

Although there should be a good reason for doing this (like, need to pass it to an API that expects exactly "x"). A single-property object is about as useful as the value of its single property.

answered May 31, 2017 at 16:53

James

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Comments

Umair · Accepted Answer · 2017-05-31 16:57:09Z

1

How about making a function and using it for other similar purposes:

function transform (prop, payload) {
  return { [prop]: payload };
}

And use it like:

phone = transform('phoneNumbers', obj.phoneNumbers);

answered May 31, 2017 at 16:57

Umair

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