First, let's go over what's being passed to fun():
print(data[0]) # This outputs the first item in 'data[]'
# Output: [[1,2], [3,4]]
Now let's break down the first line of the function. We have v=m[0][0].
print(m)
# [[1,2], [3, 4]] (What we passed to the function)
print(m[0])
# [1,2] (The first item in the list)
print(m[0][0])
# 1 (The first item of the the first item in the original list)
So this line is just getting the very first number in the nested list.
Next, the for loops:
for row in m:
print(row)
# [1,2] (iter 1)
# [3,4] (iter 2)
This is just cycling through all the list items in the list that was passed to the function.
Then, for each of those cases, we're iterating through each number:
for row in m:
for element in row:
print(element)
# 1
# 2
# 3
# 4
Lastly, the if statement is comparing the current element (1, 2, 3, and then 4) to the current value of v (which starts off as 1). If v is less than the current element, we replace v with the current element.
So, for example, in the first iteration of the loop, we compare:
if v < element (if 1 < 1)
Which is false, so we move on to the next loop, where we compare:
if 1 < 2
This is True, so we execute the next line which states v = element (or v = 2)
So on the next loop, we are now comparing:
if 2 < 3
Which is True, so v will again be assigned the value of element
At the end of both for loops, we end up returning the largest value of m, in this case: 4
data[0]. You seem to have the right idea in the question, just keep moving to the nextrowinmv(withvstarting out as the first number). Sincevstarts out as1, no other number is smaller.