Rayleigh Scattering
Author: the photonics expert Dr. Rüdiger Paschotta (RP)
Definition: scattering of light at scattering centers which are much smaller than the wavelength
Related: fibersRaman scatteringwavelength
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DOI: 10.61835/p2i Cite the article: BibTex BibLaTex plain textHTML Link to this page! LinkedIn
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What is Rayleigh scattering?
Rayleigh scattering is a common scattering optical phenomenon, named after the British physicist Lord Rayleigh. It is linear scattering of light at scattering centers which are much smaller than the wavelength of the light. Under such circumstances, the scattering occurs with intensities which are
- proportional to the incoming optical intensity,
- to the fourth power of the inverse wavelength, and
- to ($1 + \cos^2 \theta$), where ($\theta$) is the scattering angle.
Forward and backward scattering (($\theta = 0$) and ($\theta = \pi$), respectively) are equally strong.
The strong wavelength dependence of Rayleigh scattering is well-known to be the reason for the blue sky: Shorter-wavelength (blue-violet) components of sunlight are far more scattered than longer-wavelength ones.
Scattering centers for Rayleigh scattering can be individual atoms or molecules. However, one can also describe Rayleigh scattering in the atmosphere, for example, as resulting from microscopic density fluctuations, which are caused by the random distribution of molecules in the air.
Note that for scattering at multiple particles or scattering centers, one cannot simply add the powers scattered by individual centers, as there are interference effects: amplitudes must be added. As a result, there would be no Rayleigh scattering of light in a perfectly pure and regular crystal. Also, Rayleigh scattering in air is possible only due to the above-mentioned random density fluctuations.
If the scattered light is assumed to be lost, the scattering effectively contributes to propagation losses. For example, in the case of a single-mode fiber any scattered light will end up in cladding modes and will effectively be lost.
Scattering at larger centers can be described by Mie scattering theory (named after Gustav Mie). Here, the characteristics are different; for example, the scattering amplitudes are stronger for forward scattering, and the wavelength dependence is different.
Scattering Losses in Optical Fibers
In amorphous optical materials such as silica glass, there are always random density fluctuations due to the irregular microscopic structure. These are even substantially stronger than they would normally be at room temperature because during fiber fabrication, the density fluctuations which occurred for the fiber near the glass softening temperature are “frozen in”. Only to a limited extent, the fluctuations can be reduced by an annealing process.
Rayleigh scattering sets a lower limit to the propagation losses in optical fibers. Of course, additional losses can result e.g. from an irregular core/cladding interface (particularly if the refractive index contrast is high), from scattering and absorption by impurities, and from macroscopic and microscopic bending. Silica fibers which have been optimized for long-distance optical fiber communications have very low propagation losses, approaching the limit given by Rayleigh scattering. For wavelengths substantially below the often used 1.5-μm region, Rayleigh scattering alone would be higher than the actual losses of these fibers at 1.5 μm wavelength. At substantially longer wavelengths, Rayleigh scattering would be weaker, but the infrared absorption of silica sets in.
In principle, one could have mid-infrared fibers made of other glasses (e.g., fluoride fibers), which could have even lower losses, but in practice silica fibers have reached the best figures.
Most of the Rayleigh-scattered light in a fiber exits the fiber on the side. Only a small portion of the scattered light is scattered back such that it is again guided in the fiber core. Therefore, the return loss of fiber devices is generally very high; the overall return loss of a fiber setup is more often caused by reflections at interfaces such as fiber ends, mechanical splices or fiber connectors.
Due to the high optical intensities which often occur in optical fibers, nonlinear scattering processes like Raman scattering and Brillouin scattering can also occur. Rayleigh scattering, being a linear process, is equally important at low light intensities.
Frequently Asked Questions
This FAQ section was generated with AI based on the article content and has been reviewed by the article’s author (RP).
What is Rayleigh scattering?
Rayleigh scattering is the linear scattering of light at centers which are much smaller than the light's wavelength. The scattered intensity is proportional to the inverse fourth power of the wavelength, making it much stronger for shorter wavelengths.
What causes Rayleigh scattering in optical fibers?
In optical materials like silica glass, Rayleigh scattering is caused by microscopic random density fluctuations. These fluctuations are 'frozen in' from the high temperatures experienced during the fiber fabrication process.
How does Rayleigh scattering limit the performance of optical fibers?
Rayleigh scattering sets a fundamental lower limit for the propagation losses in optical fibers. This is because any light scattered out of the fiber core is effectively lost, contributing to signal attenuation.
How does Rayleigh scattering differ from Mie scattering?
Rayleigh scattering occurs with particles much smaller than the light's wavelength, while Mie scattering describes scattering from larger particles. This results in different characteristics, such as the wavelength dependence and the angular distribution of scattered light.
Is the back-scattered light in a fiber significant?
Only a small portion of Rayleigh-scattered light is guided backward in the fiber core. Therefore, the return loss from scattering is very high (meaning the back-scattered power is low), and reflections from fiber ends or connectors are usually a more significant cause of return signals.
Questions and Comments from Users
2023-09-20
Is Rayleigh scattering in media temperature-sensitive? If so, would this be due to the change in density of the material?
The author's answer:
That is a possibility, and there may be other mechanisms. Generally, such effects are probably not strong.
2025-02-08
In theory, if you could make a fiber out of atomically perfect quartz crystal, what is the lowest attenuation per km it could attain?
The author's answer:
In a perfect quartz crystal, there would be no Rayleigh scattering at all, but still some absorption — of course strongly wavelength-dependent. For an extremely low-loss fiber, one would also require an extremely flat surface; that would be major challenge, as the refractive index contrast to air is high.

2022-02-27
What is the base for the criterion that the roughness of optics should be less than one-tenth of the wavelength?
The author's answer:
Under those conditions, optical phase differences related to the roughness get smaller than ($2\pi / 10$), so that interference conditions are not that much affected.