std::asinh
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Definido no cabeçalho <cmath>
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float asinh( float arg ); |
(desde C++11) | |
double asinh( double arg ); |
(desde C++11) | |
long double asinh( long double arg ); |
(desde C++11) | |
double asinh( Integral arg ); |
(desde C++11) | |
Calcula arco seno hiperbólico de
arg
Original:
Computes hyperbolic arc sine of
arg
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You can help to correct and verify the translation. Click here for instructions.
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Índice |
[editar] Parâmetros
arg | - | flutuando valor de ponto
Original: floating point value The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
[editar] Valor de retorno
seno hiperbólico inverso de
arg
Original:
inverse hyperbolic sine of
arg
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[editar] Veja também
(C++11) |
hiperbólica arco cosseno Original: hyperbolic arc cosine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função) |
(C++11) |
arco tangente hiperbólica Original: hyperbolic arc tangent The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função) |
calcula seno hiperbólico (sh(x)) Original: computes hyperbolic sine (sh(x)) The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função) | |
(C++11) |
calcula arco seno hiperbólico de um número complexo Original: computes hyperbolic arc sine of a complex number The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) |
[editar] Links externos
Weisstein, Eric W. "Inverse Hyperbolic Sine." De MathWorld - Um recurso Web Wolfram.
Original:
Weisstein, Eric W. "Inverse Hyperbolic Sine." From MathWorld--A Wolfram Web Resource.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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