I want to get the query name and values to be displayed from a URL.
For example, url='http://host:port_num/file/path/file1.html?query1=value1&query2=value2'
From this, parse the query names and its values and to print it.
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The canonical question is How can I split a URL string up into separate parts in Python? (2009).Peter Mortensen– Peter Mortensen2022-11-28 02:36:48 +00:00Commented Nov 28, 2022 at 2:36
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2 Answers
Don't use a regex! Use urlparse.
>>> import urlparse
>>> urlparse.parse_qs(urlparse.urlparse(url).query)
{'query2': ['value2'], 'query1': ['value1']}
3 Comments
Kien Truong
And in one line
urlparse.parse_qs(urlparse.urlparse("http://www.example.com:8080/abcd/dir/file1.html?query1=value1&query2=value2").query)
Kimvais
or
[pair.split("=") for pair in urlparse(url).query.split("&")]
Peter Mortensen
That may have to be updated for Python 3.
I agree that it's best not to use a regular expression and better to use urlparse, but here is my regular expression.
Classes like urlparse were developed specifically to handle all URLs efficiently and are much more reliable than a regular expression is, so make use of them if you can.
>>> x = 'http://www.example.com:8080/abcd/dir/file1.html?query1=value1&query2=value2'
>>> query_pattern='(query\d+)=(\w+)'
>>> # query_pattern='(\w+)=(\w+)' a more general pattern
>>> re.findall(query_pattern, x)
[('query1', 'value1'), ('query2', 'value2')]
8 Comments
Li-aung Yip
It might be worth elaborating on why regex is the wrong hammer for this nail.
jamylak
Alright I think I explained it very briefly. Feel free to explain it better if you want :D
Myjab
thank you jamylak. can you plase tel me how can v split it generically. for eg. if the query contains "name=asd&name1=qwerty", for this the above pattern ll not work. so instead of using name wat v can use in the query pattern. Since i'm new to python regex i'm asking this :)
jamylak
See the commented out code,
query_pattern='(\w+)=(\w*)'. That should work for any query.Myjab
oh sorry i haven't seen it sorry
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