JSON object to PHP associative array

Question

I am building an array in JS as such:

       var slots = {}; 

                $(".taken").each(function(item) {

                    var key = $(this).attr("id");
                    slots[key] = "<?php echo $_SESSION['alias']; ?>";

                }); 

                var json = JSON.stringify(slots);
                var date = "<?php echo $_GET['date']; ?>"
             $.ajax({
                type: "POST",
                     url: "controllers/dutyupdate2.php",
                    data:{ array : json, date:  date },
                success : function(response){
                        console.log (response)
                    }//end success
                });//end ajax

In my PHP script I am posting to, I need to decode it to match the following format:

array( 'D1P'=>"JohnC" , 'D6E' => "JohnC")

I get:

Array(
    [D2E] => JohnC
    [D6E] => JohnC
    [D3BU] => JohnC
)

No matter how I decode the array, I get an indexed array with my key as the index. Am I building the array incorrectly in the JS code or decoding incorrectly?

Thanks in advance

"I get an indexed array with my key as the index" - and what exactly do you want? — Fabian Schmengler
– Fabian Schmengler, Commented Feb 14, 2013 at 15:16
I don't understand how those 2 array differ (the one you get, the one you want) — user1236048
– user1236048, Commented Feb 14, 2013 at 15:17
never echo php data directly into a Javascript context. one JS meta-character in that php data and you've killed the entire JS code block. ALWAYS use json_encode(), e.g. <?php echo json_encode($var) ?> so you always produce something syntactically valid. — Marc B
– Marc B, Commented Feb 14, 2013 at 15:18
@Jjames: The array is in the format you are looking for! print_r(array( 'D1P'=>"JohnC" , 'D6E' => "JohnC")). — gen_Eric
– gen_Eric, Commented Feb 14, 2013 at 15:59
Yes, I thought so from the beginning, IT was entirely my F-UP...:), I appreciate the answers not being to harsh...thanks again — Jjames
– Jjames, Commented Feb 14, 2013 at 16:34

Olaf Dietsche · Accepted Answer · 2013-02-14 16:05:28Z

2

This is the format you want, just displayed differently. See this PHP code to verify

$a = array( 'D1P'=>"JohnC" , 'D6E' => "JohnC");
print_r($a);

this gives

Array
(
    [D1P] => JohnC
    [D6E] => JohnC
)

as output. So, there's no need to try or search anything different.

answered Feb 14, 2013 at 16:05

Olaf Dietsche

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1 Comment

Jjames Over a year ago

You are absolutely correct, I am not sure where I was FUBAR ing it up, but it is correct, I thank you for your time

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