I'm trying to set the index of an array in Python, but it isn't acting as expected:
theThing = []
theThing[0] = 0
'''Set theThing[0] to 0'''
This produces the following error:
Traceback (most recent call last):
File "prog.py", line 2, in <module>
theThing[0] = 0;
IndexError: list assignment index out of range
What would be the correct syntax for setting an index of an array in Python?
Python lists don't have a fixed size . To set the 0th element, you need to have a 0th element:
>>> theThing = []
>>> theThing.append(12)
>>> theThing
[12]
>>> theThing[0] = 0
>>> theThing
[0]
JavaScript's array object works a bit differently than Python's, as it fills in previous values for you:
> x
[]
> x[3] = 5
5
> x
[undefined × 3, 5]
theThing.append(12) affect the array here?
theThing.append(12) adds a 12 at the end of the (currently empty) array.
0th element. I just added .append(12) to give the list one. JavaScript's syntax is probably throwing you off here.thing = [None for i in range(10)], but the list will still contain 10 elements.You're trying to assign to a non-existent position. If you want to add an element to the list, do
theThing.append(0)
If you really want to assign to index 0 then you must ensure the list is non-empty first.
theThing = [None]
theThing[0] = 0
It depends on what you really need. First you have to read python tutorials about list. In you case you can use smth like:
lVals = []
lVals.append(0)
>>>[0]
lVals.append(1)
>>>[0, 1]
lVals[0] = 10
>>>[10, 1]
theThing = []creates an empty array, so the index 0 doesn't exist.var theThing = new Array(); theThing[0] = 0;to set the 0th element oftheThingto 0.theThing[0]=0, trytheThing.append(0).