jQuery: how to access certain values within an array

Question

I am new to arrays in jQuery. If I have an array that looks as follows, is there a way that I can access just the numbers (without the item names) ?

I would to extract the group of numbers for each item, so instead of "item1: 5, 7, 9" I would need just "5, 7, 9" etc.

var arr = 
{
    item1: 5, 7, 9
    item2: 3, 5, 3
    item3: 1, 7, 5
    //...
}

That's not an array. It's an object. That's also not even valid JavaScript syntax. What exactly do you have? Does arr.item1 work for you? — gen_Eric
– gen_Eric, Commented Apr 7, 2014 at 20:14
It would be a valid Javascript syntax if items are arrays: item1: [5, 7, 9] and so on... — Justin Iurman
– Justin Iurman, Commented Apr 7, 2014 at 20:15
Thanks. Yes, it looks like Justin's example - sorry, I typed that wrong. — user2571510
– user2571510, Commented Apr 7, 2014 at 20:16

Justin Iurman · Accepted Answer · 2014-04-07 20:43:49Z

1

Valid syntax:

var arr = 
{
    item1: [5, 7, 9],
    item2: [3, 5, 3],
    item3: [1, 7, 5]
}

Calling arr.item1 will give you back an array: item1.
Since arr is an object, you can access its items (keys) like properties.

If you want first number from that array, you can use arr.item1[0].
In a more dynamic way, you could use each:

$.each(arr.item1, function(key, value) 
{
   console.log('item1 contains number ' + value);
});

Output:

item1 contains number 5
item1 contains number 7
item1 contains number 9

answered Apr 7, 2014 at 20:19

Justin Iurman

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Comments

Adam · Accepted Answer · 2014-04-07 20:18:48Z

1

The syntax you are looking for is:

var arr = 
{
    "item1": [5, 7, 9],
    "item2": [3, 5, 3],
    "item3": [1, 7, 5]
}

And you can access it with arr["item1"] and that will return [5,7,9].

You could also do it as:

var arr = 
[
    [5, 7, 9],
    [3, 5, 3],
    [1, 7, 5]
]

And access it as arr[0] with a return of [5,7,9]

answered Apr 7, 2014 at 20:18

Adam

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