Sort one array based on another array using javascript

Question

I have two arrays

MRP [60 80 82 50 80 80 ]
Brand [ A B C D E F ]

I need to get top two brands based on MRP. highest two in MRP is 82 ,80 but 80 is 3 times repeated so i need all repeated values as well to get top two brands. i.e i need to display [C B E F]

For that i sorted MRP in descending order.Now MRP after sorting become [ 82 80 80 60 50 ]

Now i need to sort Brand Array based on Sorted MRP.Can some one help in this sorting using javascript .

Any attempts on your own so far? Is this Java or JavaScript? — Sirko
– Sirko, Commented Jun 13, 2014 at 8:54
@ZiNNED I only sorted the first array ie MRP bt not the brands.but now i got the solution shared by Nishanthi Grashia in the subsequent post. — Hemant Singh
– Hemant Singh, Commented Jun 13, 2014 at 9:45

ngrashia · Accepted Answer · 2014-06-13 08:55:12Z

9

Try below code

var A = [60, 80, 82, 50, 80, 80];
var B = ['a', 'b', 'c', 'd', 'e', 'f'];

var all = [];

for (var i = 0; i < B.length; i++) {
    all.push({ 'A': A[i], 'B': B[i] });
}

all.sort(function(a, b) {
  return b.A - a.A;
});

A = [];
B = [];

for (var i = 0; i < all.length; i++) {
   A.push(all[i].A);
   B.push(all[i].B);
}    

alert(A);
alert( B);

answered Jun 13, 2014 at 8:55

ngrashia

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1 Comment

ngrashia Over a year ago

Happy to help! Please also upvote and accept as answer if it helped.

hughes · Accepted Answer · 2015-06-29 22:24:03Z

0

Using lodash/underscore:

var A = [60, 80, 82, 50, 80, 80];
var B = ['a', 'b', 'c', 'd', 'e', 'f'];

var result = _.unzip(_.sortBy(_.zip(A, B), '-0'));

var A_sorted = result[0]; // [82, 80, 80, 80, 60, 50]
var B_sorted = result[1]; // ["c", "b", "e", "f", "a", "d"]]

answered Jun 29, 2015 at 22:24

hughes

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