Cannot convert String to int in Java

Question

In my program I need to convert a String to Int.

    String str = new String(request.getData());

    String [] setting = str.split(" ");        
    String bs = setting[1];

The value of bs is 1024, I use System.out.println to test it, and it displays on the screen with "1024".

But when I use

    int blockSize = Integer.parseInt(bs);

it will return an exception point to the line of Integer.parseInt :

Exception in thread "main" java.lang.NumberFormatException: For input string: "1024"
  at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
  at java.lang.Integer.parseInt(Integer.java:458)
  at java.lang.Integer.valueOf(Integer.java:554)

Can someone help me to solve it? Thanks.

Are you sure bs contains 1024, because if so, then you shouldn't be getting any problem. — lxcky
– lxcky, Commented Sep 20, 2014 at 7:15
@darknight, I don't think it's an issue of excessive whitespace since he's using a space as a delimiter. — lxcky
– lxcky, Commented Sep 20, 2014 at 7:17
i think your bs contains string value not a integer that's why this error. make sure setting[postion] is an integer value. i mean like "somevalue". — Rustam
– Rustam, Commented Sep 20, 2014 at 7:22
@jacobbb - I suspect you have invisible characters in there. bs.length() would probably be helpful, and possibly even a loop over the characters outputting their character code: for (char ch : bs.toCharArray() ) { System.out.println(Integer.toHexString(ch)); } — T.J. Crowder
– T.J. Crowder, Commented Sep 20, 2014 at 7:23
I think the issue is with some unicode hidden character. Test the length of the string and check if it is really 4. — enrico.bacis
– enrico.bacis, Commented Sep 20, 2014 at 7:23

enrico.bacis · Accepted Answer · 2014-09-20 08:38:04Z

10

I suspect you have some hidden unicode character in the string bs, you can remove the non-digits with:

bs = bs.replaceAll("\\D", "");
int blockSize = Integer.parseInt(bs);

The code above will also convert the string "1a2" to 12, but that doesn't seem your case.

edited Sep 20, 2014 at 8:38

answered Sep 20, 2014 at 7:41

enrico.bacis

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2 Comments

jacobbb Over a year ago

I tried bs.length(), the return value is 1019... and I used "bs = bs.replaceAll("\\D", "");" , problem solved, thanks.

jacobbb Over a year ago

yeah..1019..idk why, the array setting[] is i sending from datagramSocket, is there sth to do with this?

hossein ketabi · Accepted Answer · 2014-12-15 05:05:40Z

1

try this code:

 String bs = setting[1].trim().toString();

answered Dec 15, 2014 at 5:05

hossein ketabi

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Comments

Mikeologist · Accepted Answer · 2014-09-20 07:45:37Z

    while( (!bs.matches("\\d+")) && (bs.length > 1)) 
    {
        bs = bs.substring(1);
    }

    if (bs.matches("\\d+")
    {
        int blockSize = Integer.parseInt(bs);
    }
    else
    {
        int blockSize = -1;
    }
    /* !! Then, check for "-1" in your application of 
          block size #runtime_exception_prevention */

This will continue to remove the offensive non digit bits down to 1, as necessary, until a digit is found or only one character remains in the string. The second check prevents the exception and returns a flagged value. Checking for this flagged value will intercept runtime exceptions. NB: I wrote this code in the comment block, please forgive any minor errors, I will gladly correct.

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