How do I get the App version and build number using Swift?

Question

I have an IOS app with an Azure back-end, and would like to log certain events, like logins and which versions of the app users are running.

How can I return the version and build number using Swift?

Answer 1

EDIT

Updated for Swift 4.2

let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String

EDIT

As pointed out by @azdev on the new version of Xcode you will get a compile error for trying my previous solution, to solve this just edit it as suggested to unwrap the bundle dictionary using a !

let nsObject: AnyObject? = Bundle.main.infoDictionary!["CFBundleShortVersionString"]

End Edit

Just use the same logic than in Objective-C but with some small changes

//First get the nsObject by defining as an optional anyObject
let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary["CFBundleShortVersionString"]

//Then just cast the object as a String, but be careful, you may want to double check for nil
let version = nsObject as! String

Answer 2

Updated for Swift 3.0

The NS-prefixes are now gone in Swift 3.0 and several properties/methods have changed names to be more Swifty. Here's what this looks like now:

extension Bundle {
    var releaseVersionNumber: String? {
        return infoDictionary?["CFBundleShortVersionString"] as? String
    }
    var buildVersionNumber: String? {
        return infoDictionary?["CFBundleVersion"] as? String
    }
}

Bundle.main.releaseVersionNumber
Bundle.main.buildVersionNumber

Old Updated Answer

I've been working with Frameworks a lot since my original answer, so I wanted to update my solution to something that is both simpler and much more useful in a multi-bundle environment:

extension NSBundle {

    var releaseVersionNumber: String? {
        return self.infoDictionary?["CFBundleShortVersionString"] as? String
    }

    var buildVersionNumber: String? {
        return self.infoDictionary?["CFBundleVersion"] as? String
    }

}

Now this extension will be useful in apps to identify both the main bundle and any other included bundles (such as a shared framework for extension programming or third frameworks like AFNetworking), like so:

NSBundle.mainBundle().releaseVersionNumber
NSBundle.mainBundle().buildVersionNumber

// or...

NSBundle(URL: someURL)?.releaseVersionNumber
NSBundle(URL: someURL)?.buildVersionNumber

---

Original Answer

I wanted to improve on some of the answers already posted. I wrote a class extension that can be added to your tool chain to handle this in a more logical fashion.

extension NSBundle {

class var applicationVersionNumber: String {
    if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"]

as? String { return version } return "Version Number Not Available" }

class var applicationBuildNumber: String {
    if let build = NSBundle.mainBundle().infoDictionary?["CFBundleVersion"] as? String {
        return build
    }
    return "Build Number Not Available"
}

}

So now you can access this easily by:

let versionNumber = NSBundle.applicationVersionNumber

Answer 3

I know this has already been answered but personally I think this is a little cleaner:

Swift 3.0:

 if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
    self.labelVersion.text = version
}

Swift <2.3

if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"] as? String {
    self.labelVersion.text = version
}

This way, the if let version takes care of the conditional processing (setting the label text in my case) and if infoDictionary or CFBundleShortVersionString are nil the optional unwrapping will cause the code to be skipped.

Answer 4

I also know this has already been answered but I wrapped up the previous answers:

(*)Updated for extensions

extension Bundle {
    var releaseVersionNumber: String? {
        return infoDictionary?["CFBundleShortVersionString"] as? String
    }
    var buildVersionNumber: String? {
        return infoDictionary?["CFBundleVersion"] as? String
    }
    var releaseVersionNumberPretty: String {
        return "v\(releaseVersionNumber ?? "1.0.0")"
    }
}

Usage:

someLabel.text = Bundle.main.releaseVersionNumberPretty

@Deprecated: Old answers

Swift 3.1:

class func getVersion() -> String {
    guard let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String else {
        return "no version info"
    }
    return version
}

For older versions:

class func getVersion() -> String {
    if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"] as? String {
        return version
    }
    return "no version info"
}

So if you want to set label text or want to use somewhere else;

self.labelVersion.text = getVersion()

Answer 5

2025, Swift 3-∞

extension Bundle {
    public var appName: String           { getInfo("CFBundleName") }
    public var displayName: String       { getInfo("CFBundleDisplayName") }
    public var language: String          { getInfo("CFBundleDevelopmentRegion") }
    public var identifier: String        { getInfo("CFBundleIdentifier") }
    public var copyright: String         { getInfo("NSHumanReadableCopyright").replacingOccurrences(of: "\\\\n", with: "\n") }
    
    public var appBuild: String          { getInfo("CFBundleVersion") }
    public var appVersionLong: String    { getInfo("CFBundleShortVersionString") }
    //public var appVersionShort: String { getInfo("CFBundleShortVersion") }
    
    fileprivate func getInfo(_ str: String) -> String { infoDictionary?[str] as? String ?? "⚠️" }
}

usage (SwiftUI sample):

Text("Ver: \(Bundle.main.appVersionLong) (\(Bundle.main.appBuild)) ")

Text(Bundle.main.copyright)
    .font(.system(size: 10, weight: .thin))
    .multilineTextAlignment(.center)

Bonus: Copyright supports \n symbols!

Answer 6

Swift 5 as UIApplication extension

extension UIApplication {
    static var release: String {
        return Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") as! String? ?? "x.x"
    }
    static var build: String {
        return Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") as! String? ?? "x"
    }
    static var version: String {
        return "\(release).\(build)"
    }
}

example use:

print("release: \(UIApplication.release)")
print("build: \(UIApplication.build)")
print("version: \(UIApplication.version)")

Answer 7

For Swift 4.0

let version = Bundle.main.infoDictionary!["CFBundleShortVersionString"]!
let build = Bundle.main.infoDictionary!["CFBundleVersion"]!

Answer 8

I made an Extension on Bundle

extension Bundle {

    var appName: String {
        return infoDictionary?["CFBundleName"] as! String
    }

    var bundleId: String {
        return bundleIdentifier!
    }

    var versionNumber: String {
        return infoDictionary?["CFBundleShortVersionString"] as! String 
    }

    var buildNumber: String {
        return infoDictionary?["CFBundleVersion"] as! String
    }

}

and then use it

versionLabel.text = "\(Bundle.main.appName) v \(Bundle.main.versionNumber) (Build \(Bundle.main.buildNumber))"

Answer 9

Bundle+Extension.swift (SwiftUI, Swift 5, Xcode 11)

I combined ideas from a few answers, and extended a bit:

• a SwiftUI example
• Displays a warning triangle emoticon (rather than crashing the app) if the key is missing from the Info.plist

---

import Foundation

extension Bundle {
    
    public var appVersionShort: String {
        if let result = infoDictionary?["CFBundleShortVersionString"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
    public var appVersionLong: String {
        if let result = infoDictionary?["CFBundleVersion"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
    public var appName: String {
        if let result = infoDictionary?["CFBundleName"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
}

---

SwiftUI example use

VStack {

     Text("Version: \(Bundle.main.appVersionShort!) (\(Bundle.main.appVersionLong!))")
                    .font(.subheadline)
                    .frame(maxWidth: .infinity, maxHeight: .infinity)
}

Answer 10

I created an extension for UIApplication.

extension UIApplication {
    static var appVersion: String {
        let versionNumber = Bundle.main.infoDictionary?[IdentifierConstants.InfoPlist.versionNumber] as? String
        let buildNumber = Bundle.main.infoDictionary?[IdentifierConstants.InfoPlist.buildNumber] as? String
        
        let formattedBuildNumber = buildNumber.map {
            return "(\($0))"
        }

        return [versionNumber,formattedBuildNumber].compactMap { $0 }.joined(separator: " ")
    }
}

enum Constants {
    enum InfoPlist {
        static let versionNumber = "CFBundleShortVersionString"
        static let buildNumber = "CFBundleVersion"
    }
}

Answer 11

For Swift 3.0 NSBundle doesn't work, Following code works perfectly.

let versionNumberString =
      Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString")
          as! String

and for just the build number, it is:

let buildNumberString =
      Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion")
          as! String

Confusingly 'CFBundleVersion' is the build number as entered in Xcode on General->Identity.

Answer 12

Xcode 9.4.1 Swift 4.1

Note the use of localizedInfoDictionary to pick up the right language version of the bundle display name.

var displayName: String?
var version: String?
var build: String?

override func viewDidLoad() {
    super.viewDidLoad()

    // Get display name, version and build

    if let displayName = Bundle.main.localizedInfoDictionary?["CFBundleDisplayName"] as? String {
        self.displayName = displayName
    }
    if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
        self.version = version
    }
    if let build = Bundle.main.infoDictionary?["CFBundleVersion"] as? String {
        self.build = build
    }
}

Answer 13

Xcode 8, Swift 3:

let gAppVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") ?? "0"
let gAppBuild = Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") ?? "0"

Answer 14

OP asked for both version number and build number. Unfortunately most of the answers don't provide both of those options. Additionally, others add unnecessary extension methods. Here's one that's pretty simple and solves OP's problem:

// Example output: "1.0 (234)"
private func versionAndBuildNumber() -> String {
  let versionNumber = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
  let buildNumber = Bundle.main.infoDictionary?["CFBundleVersion"] as? String
  if let versionNumber = versionNumber, let buildNumber = buildNumber {
    return "\(versionNumber) (\(buildNumber))"
  } else if let versionNumber = versionNumber {
    return versionNumber
  } else if let buildNumber = buildNumber {
    return buildNumber
  } else {
    return ""
  }
}

Answer 15

Swift 4, useful Extension for Bundle

import Foundation

public extension Bundle {

    public var shortVersion: String {
        if let result = infoDictionary?["CFBundleShortVersionString"] as? String {
            return result
        } else {
            assert(false)
            return ""
        }
    }

    public var buildVersion: String {
        if let result = infoDictionary?["CFBundleVersion"] as? String {
            return result
        } else {
            assert(false)
            return ""
        }
    }

    public var fullVersion: String {
        return "\(shortVersion)(\(buildVersion))"
    }
}

Answer 16

Bundle+Extensions.swift

import Foundation

extension Bundle {
    var versionNumber: String? {
        return infoDictionary?["CFBundleShortVersionString"] as? String
    }

    var buildNumber: String? {
        return infoDictionary?["CFBundleVersion"] as? String
    }

    var bundleName: String? {
        return infoDictionary?["CFBundleName"] as? String
    }
}

Usage:

someLabel.text = Bundle.main.versionNumber

Answer 17

My answer (as at Aug 2015), given Swift keeps evolving:

let version = NSBundle.mainBundle().infoDictionary!["CFBundleVersion"] as! String

Answer 18

For Swift 5.0 :

let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as! String

Answer 19

Having looked at the documentation, I believe that the following is cleaner:

let version = 
NSBundle.mainBundle().objectForInfoDictionaryKey("CFBundleShortVersionString") 
as? String

Source: "Use of this method is preferred over other access methods because it returns the localized value of a key when one is available."

Answer 20

Swift 5.3

let infoDictionaryKey = kCFBundleVersionKey as String
guard let currentVersion = Bundle.main.object(forInfoDictionaryKey: infoDictionaryKey) as? String
else { fatalError("Expected to find a bundle version in the info dictionary") }

Answer 21

For Swift 1.2 it's:

let version = NSBundle.mainBundle().infoDictionary!["CFBundleShortVersionString"] as! String
let build = NSBundle.mainBundle().infoDictionary!["CFBundleVersion"] as! String

Answer 22

Swift 3:

Version Number

if let versionNumberString = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String { // do something }

Build number

if let buildNumberString = Bundle.main.infoDictionary?["CFBundleVersion"] as? String { // do something }

Answer 23

Update for Swift 5

here's a function i'm using to decide whether to show an "the app updated" page or not. It returns the build number, which i'm converting to an Int:

if let version: String = Bundle.main.infoDictionary?["CFBundleVersion"] as? String {
        guard let intVersion = Int(version) else { return }
        
        if UserDefaults.standard.integer(forKey: "lastVersion") < intVersion {
            print("need to show popup")
        } else {
            print("Don't need to show popup")
        }
        
        UserDefaults.standard.set(intVersion, forKey: "lastVersion")
    }

If never used before it will return 0 which is lower than the current build number. To not show such a screen to new users, just add the build number after the first login or when the on-boarding is complete.

Answer 24

Here's an updated version for Swift 3.2:

extension UIApplication
{
    static var appVersion:String
    {
        if let appVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString")
        {
            return "\(appVersion)"
        }
        return ""
    }

    static var buildNumber:String
    {
        if let buildNum = Bundle.main.object(forInfoDictionaryKey: kCFBundleVersionKey as String)
        {
            return "\(buildNum)"
        }
        return ""
    }

    static var versionString:String
    {
        return "\(appVersion).\(buildNumber)"
    }
}

Answer 25

Swift 4

func getAppVersion() -> String {
    return "\(Bundle.main.infoDictionary!["CFBundleShortVersionString"] ?? "")"
}

Bundle.main.infoDictionary!["CFBundleShortVersionString"]

Swift old syntax

let appVer: AnyObject? = NSBundle.mainBundle().infoDictionary!["CFBundleShortVersionString"]

Answer 26

extension UIApplication {

    static var appVersion: String {
        if let appVersion = NSBundle.mainBundle().objectForInfoDictionaryKey("CFBundleShortVersionString") {
            return "\(appVersion)"
        } else {
            return ""
        }
    }

    static var build: String {
        if let buildVersion = NSBundle.mainBundle().objectForInfoDictionaryKey(kCFBundleVersionKey as String) {
            return "\(buildVersion)"
        } else {
            return ""
        }
    }

    static var versionBuild: String {
        let version = UIApplication.appVersion
        let build = UIApplication.build

        var versionAndBuild = "v\(version)"

        if version != build {
            versionAndBuild = "v\(version)(\(build))"
        }

        return versionAndBuild
    }

}

Attention: You should use if let here in case that the app version or build is not set which will lead to crash if you try to use ! to unwrap.

Answer 27

You can now use a constant for this, rather than having to use stringly-typed code like before, which makes things even more convenient.

var appVersion: String {
    return Bundle.main.infoDictionary![kCFBundleVersionKey as String] as! String
}

Answer 28

Simple utility function to return App version as Int

func getAppVersion() -> Int {

        if let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {

            let appVersionClean = appVersion.replacingOccurrences(of: ".", with: "", options: NSString.CompareOptions.literal, range:nil)

            if let appVersionNum = Int(appVersionClean) {
                return appVersionNum
            }
        }
        return 0
    }

Answer 29

public var appVersionNumberString: String {
    get {
        return Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") as! String
    }
}

Answer 30

if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
            self.lblAppVersionValue.text = version
        }