Creating multiple numpy arrays

Question

Currently, I have this piece of code to create a numpy array

X=np.array([[]]);

if (X.shape[1] == 0):
      X = np.array([vd]);
    else:
      X = np.concatenate((X,np.array([vd])));

I would now like to get multiple numpy arrays X(1) , X(2) etc for different conditions. What is the best way to do this in python. In matlab I can accomplish this using matlab struct.

Numlet · Accepted Answer · 2015-07-06 10:18:21Z

1

You can use a python dictionary for this purpose For example

import numpy as np
dic={}
dic['1']=np.zeros(3)
dic['2']=np.ones(5)
print dic['1']
print dic['2']

now dic['1'] and dic['2'] are you arrays

answered Jul 6, 2015 at 10:18

Numlet

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2 Comments

user4543816 Over a year ago

can it be dic[1]=np.zeros(3) ?

Numlet Over a year ago

Yes, it can be like that as well

sukhbinder · Accepted Answer · 2015-07-06 13:58:37Z

0

I see @user3510686 has already answered it. Posing what I tried.

a={}
for i in range(10):
    a[i]=np.random.rand(10)

answered Jul 6, 2015 at 13:58

sukhbinder

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