I have a string fullstr = "my|name|is|will" , and i would like to extract the substring "name".
I used string.find to find the first position of '|' like this:
pos = fullstr.find('|')
and it return 2 as the first position of '|' . I want to print substring from pos position until next '|'. There's rsplit feature, but it return the very first char from right of string, since there're many '|' in my string. How to print the substring?
You can still use find if you want, find first position of | and next one:
fullstr = "my|name|is|will"
begin = fullstr.find('|')+1
end = fullstr.find('|', begin)
print fullstr[begin:end]
Similar way using index:
fullstr = "my|name|is|will"
begin = fullstr.index('|')+1
end = fullstr.index('|', begin)
print fullstr[begin:end]
Another way is to find all occurrences of | in your string using re.finditer and slice it by indexes:
import re
all = [sub.start() for sub in re.finditer('\|', fullstr)]
print fullstr[all[0]+1:all[1]]
You can also take a look into re.search:
import re
fullstr = "my|name|is|will"
print re.search(r'\|([a-z]+)\|', fullstr).group(1)
There is an interesting way using enumerate:
fullstr = "my|name|is|will"
all = [p for p, e in enumerate(fullstr) if e == '|']
print fullstr[all[0]+1:all[1]]
And the easiest way just using split or rsplit:
fullstr = "my|name|is|will"
fullstr.split('|')[1]
fullstr.rsplit('|')[1]
You can use
fullstr.split("|")[1]
which will break the string apart at the "|" marks and return a list. Grabbing the second item (lists are 0-indexed, so this is index 1) will return the desired result.
Use the split() method to break up a string by one character.
fullstr.split('|') == ['my', 'name', 'is', 'will']
And then what you want is here:
fullstr.split('|')[1] == 'name'
"|", then simply usesullstr.split("|"), which would result in["my", "name", "is", "will"]