Class - Function Objects - PHP

Question

I noticed on magento, they call a function which is referenced as an object like:

className::function('example')->example;

Which to me makes no sense how it works? I tried to mimic this inside a test file but I get nothing.

<?php

class Example
{

    public function test($arg)
    {
        $want = new ExampleTwo;
        return 1;
    }

}

class ExampleTwo
{
    public $want;
    public function urgh($arg)
    {
        $this->want = "returnn";
    }
}

$Obj = new Example;
echo $Obj->test('random')->want;

NOTICE Trying to get property of non-object on line number 24

Can anyone please explain how the function becomes an Object? and if so, how can I then get values from the function object.

Function needs to return an object not a string

B-and-P
– B-and-P

2016-03-17 13:07:01 +00:00
Commented Mar 17, 2016 at 13:07 — B-and-P
– B-and-P, Commented Mar 17, 2016 at 13:07

Blaatpraat · Accepted Answer · 2016-03-17 13:07:33Z

3

If you return an object in a function, you can call that object directly from the function returned value.

In your test case:

public function test($arg)
{
    $want = new ExampleTwo;
    return $want;
}

If you have this:

$Obj = new Example;
echo $Obj->test('random')->want

This will echo the "want" property of the ExampleTwo class, which will be NULL in your example code.

answered Mar 17, 2016 at 13:07

Blaatpraat

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2 Comments

Jaquarh Over a year ago

Wow, that actually makes more sense, I actually didn't know you could do this? That's awesome, you can even add functions and call functions ->anotherTest('?')->andAnother('ssss'); thats mad

Jaquarh Over a year ago

this adds a whole new dimension to object orientated programming :o Appreciated!

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