Get binary data from string

Question

After sending some information through a socket i have a binary object that looks like this:

b"1:b'5Q\x19aw\x17\x8c\x98\x10\x1c\xe0O\x14\xd1x\xa1'"

What I want to do is get the first part before the : as a string and the second as a binary. Like this:

'1'

and:

b'5Q\x19aw\x17\x8c\x98\x10\x1c\xe0O\x14\xd1x\xa1'

With all my attempts I ended up with either:

b"b'5Q\x19aw\x17\x8c\x98\x10\x1c\xe0O\x14\xd1x\xa1'"

or:

"b'5Q\x19aw\x17\x8c\x98\x10\x1c\xe0O\x14\xd1x\xa1'"

Dimitris Fasarakis Hilliard · Accepted Answer · 2017-05-08 00:26:36Z

1

Just split it on b':' and decode and trim accordingly:

i, j = r.split(b':')
i = i.decode()  #  '1'
j = j[2:-1]

Now:

print(i)
# 1
print(j)
# b'5Q\x19aw\x17\x8c\x98\x10\x1c\xe0O\x14\xd1x\xa1'

answered May 8, 2017 at 0:26

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1 Comment

Thank you, so simple. Actually instead of j = j[2:-1] i just used j. Otherwise i get only part of the message.