for string "//div[@id~'objectnavigator-card-list']//li[@class~'outbound-alert-settings']", I want to find "@..'...'" like "@id~'objectnavigator-card-list'" or "@class~'outbound-alert-settings'". But when I use regex ((@.+)\~(\'.*?\')), it find "@id~'objectnavigator-card-list']//li[@class~'outbound-alert-settings'". So how to modify the regex to find the string successfully?
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Please format question properly.Rahul– Rahul2017-05-15 03:13:34 +00:00Commented May 15, 2017 at 3:13
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3 Answers
Use non-capturing, non greedy, modifiers on the inner brackets and search for not the terminating character, e.g.:
re.findall(r"((?:@[^\~]+)\~(?:\'[^\]]*?\'))", test)
On your test string returns:
["@id~'objectnavigator-card-list'", "@class~'outbound-alert-settings'"]
Comments
Limit the characters you want to match between the quotes to not match the quote:
>>> re.findall(r'@[a-z]+~\'[-a-z]*\'', x)
I find it's much easier to look for only the characters I know are going to be in a matching section rather than omitting characters from more permissive matches.
Comments
For your current test string's input you can try this pattern:
import re
a = "//div[@id~'objectnavigator-card-list']//li[@class~'outbound-alert-settings']"
# find everything which begins by '@' and neglect ']'
regex = re.compile(r'(@[^\]]+)')
strings = re.findall(regex, a)
# Or simply:
# strings = re.findall('(@[^\\]]+)', a)
print(strings)
Output:
["@id~'objectnavigator-card-list'", "@class~'outbound-alert-settings'"]
