PHP json_decode returns null on valid string

Question

I have the following code:

$option = $this->request->post['option'];

var_dump($option);
echo "<br>";
var_dump(json_decode($option));

The dumps show:

string(118) "{'product_option_id':276, 'product_option_value_id':132, 'name':'Цветове', 'value':'Бял', 'type':'select'}"

And the second one (json_decode):

NULL

Why the string can't be parsed ?

EDIT: now my json looks like this:

string(205) "{"product_option_id": 280, "product_option_value_id": 133, "name": "Цветове", "value": "Бежов", "type": "select"}"

And i added this to my code:

switch (json_last_error()) {
        case JSON_ERROR_NONE:
            echo ' - No errors';
        break;
        case JSON_ERROR_DEPTH:
            echo ' - Maximum stack depth exceeded';
        break;
        case JSON_ERROR_STATE_MISMATCH:
            echo ' - Underflow or the modes mismatch';
        break;
        case JSON_ERROR_CTRL_CHAR:
            echo ' - Unexpected control character found';
        break;
        case JSON_ERROR_SYNTAX:
            echo ' - Syntax error, malformed JSON';
        break;
        case JSON_ERROR_UTF8:
            echo ' - Malformed UTF-8 characters, possibly incorrectly encoded';
        break;
        default:
            echo ' - Unknown error';
        break;
    }

and i returns Syntax error, malformed JSON

Question: What character encoding scheme are you using? If anything other than UTF-8 that may be your problem. — Simba
– Simba, Commented Sep 19, 2017 at 10:13

miron · Accepted Answer · 2017-09-19 09:15:24Z

1

See this SO answer: https://stackoverflow.com/a/4162651/174326

If you wrap your strings in your JSON string with double quotes it'll work: json_decode('{"product_option_id":276, "product_option_value_id":132, "name":"Цветове", "value":"Бял", "type":"select"}')

answered Sep 19, 2017 at 9:15

miron

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1 Comment

Angel Miladinov Over a year ago

I've done it the result is still the same my first dump now looks like this:

string(196) "{"product_option_id":276, "product_option_value_id":132, "name":"Цветове", "value":"Бял", "type":"select"}"

Leo Aso · Accepted Answer · 2017-09-19 09:20:14Z

1

Single quotes are not allowed in JSON, only double quotes. Do

$option = str_replace ("'", '"', $option);

before calling json_decode.

answered Sep 19, 2017 at 9:20

Leo Aso

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1 Comment

Angel Miladinov Over a year ago

now its looks like this:

string(196) "{"product_option_id":276, "product_option_value_id":132, "name":"Цветове", "value":"Бял", "type":"select"}"

, but the result is still null

ajith mohan · Accepted Answer · 2017-09-19 09:22:29Z

0

refer Convert a string to JSON object php

you can use

$result = (array) json_decode($option);

or

$result = json_decode($option, true);

answered Sep 19, 2017 at 9:22

ajith mohan

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1 Comment

Angel Miladinov Over a year ago

when you convert null to array you receive array(0) {}

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