My Code Scenario is:
var Employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246},
{name:"madhu",htno:1247},{name:"ranga",htno:1248}]
var seletedEmployees= [{name:"mohan"},{name:"ranga"}];
var employeesdataAfterremoveSelected = [?];
6 Answers
You can store selected employees names in an array and then filter Employees array and check if employee's name is in this array:
var employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246},{name:"madhu",htno:1247},{name:"ranga",htno:1248}]
var selectedEmployees= ["mohan","ranga"];
var result = employees.filter(emp => selectedEmployees.includes(emp.name));
console.log(result);To programatically get array of strings instead array of objects, you can use map:
var seletedEmployees= [{name:"mohan"},{name:"ranga"}].map(emp => emp.name);
Comments
From the code you have given above i think this might work
$.each(student, function(key, value){
if(matchedvalues.indexOf(value.name) < 0)
{
employeesdataAfterremoveSelected.push(value.name);
}
})
Comments
Here is a one liner, decomposed to explain :
// Start by filtering the first array on a condition.
employeesdataAfterremoveSelected = Employees.filter(
// Map the array of selected employees to only return the name
e => seletedEmployees.map(_e => _e.name)
// use the includes function to check if the name is in the array
.includes(e.name)
);
In one line :
employeesdataAfterremoveSelected = Employees.filter(e => seletedEmployees.map(_e => _e.name).includes(e.name));
Comments
You can use the filter method, something like below (not tested)
var Employees = [{name:"Ram",htno:1245}, {name:"mohan",htno:1246}]
var SelectedEmployess = [{name:"Ram",htno:1245}]
// filter the items from the invalid list, out of the complete list
var employeesdataAfterremoveSelected = Employees.filter((item.name) => {
return !SelectedEmployess.has(item.name);
})
// get a Set of the distinct, valid items
var validItems = new Set(employeesdataAfterremoveSelected);
Comments
You can try this:
var Employees = [{name:"Ram",htno:1245},{name:"mohan",htno:1246},
{name:"madhu",htno:1247},{name:"ranga",htno:1248}]
var seletedEmployees = [{name:"mohan"},{name:"ranga"}];
var employeesdataAfterremoveSelected = Employees.filter(name => {
return (name.name !== seletedEmployees[0].name && name.name !== seletedEmployees[1].name)
})
console.log(employeesdataAfterremoveSelected)
1 Comment
Rambabu Bommisetti
if i want to remove one more element instead of var seletedEmployees = [{name:"mohan"},{name:"ranga"}]; i want to delete var seletedEmployees = [{name:"mohan"},{name:"ranga"},{name:"Rambabu"}]; how can I achieve without hard coded inde values as [0] , [1] ....
var Employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246}, {name:"madhu",htno:1247},{name:"ranga",htno:1248}]
var seletedEmployees= [{name:"mohan"},{name:"ranga"}];
var employeesdataAfterremoveSelected = Employees.filter(function(val,index) { console.log(val.name) return !(seletedEmployees.map(function(e) { return e.name; }).indexOf(val.name)); });
Employees.filter(emp => seletedEmployees.every(semp => semp.name !== emp.name))