print(['at', 'from', 'hello', 'hi', 'there', 'this'].sort())
returns
None
1: https://thispointer.com/python-how-to-sort-a-list-of-strings-list-sort-tutorial-examples/
2: How to sort a list of strings?
I saw two examples, but why not work?
-
1Possible duplicate of Python Sort() methodabhilb– abhilb2019-11-13 06:19:15 +00:00Commented Nov 13, 2019 at 6:19
Add a comment
|
2 Answers
sort() doesn't have return value, so it return default None. It modifies the original list, so you need to use it on a list name
l = ['at', 'from', 'hello', 'hi', 'there', 'this']
l.sort()
print(l)
If you don't want do modify the list you can create sorted copy with sorted()
l = ['at', 'from', 'this', 'there', 'hello', 'hi']
print(sorted(l)) # prints sorted list ['at', 'from', 'hello', 'hi', 'there', 'this']
print(l) # prints the original ['at', 'from', 'this', 'there', 'hello', 'hi']
Comments
I think this has to do with the function sort() and where it works. sort() will only act upon a mutable data type, which must be a list or something like it. It has no return, it only modifies a data type. This is why it will return a sorted list, as the list has passed through the sort() function. When you run this program:
>>> i = ['at', 'from', 'hello', 'hi', 'there', 'this']
>>> i.sort()
>>> print(i)
['at', 'from', 'hello', 'hi', 'there', 'this']
>>>
It works fine, as the sort() function is being called to a variable.
