Conditions on itertools combinations Python

Question

I would like to pre definited a condition on itertools combinations.

My problem: I need only combinations with 100 or less days difference.

Actually my code breaks the loop. I would like to cut and continue with the next combinations. Is it possible?

from itertools import combinations
for row in combinations(df.values, 5):
    E1_date, E2_date, E3_date, E4_date, E5_date = row[0][0], row[1][0], row[2][0], row[3][0], row[4][0]
    if E5_date - E1_date > 100:
        break
        # The combinations must not have more than 100 days of difference

Yes but I dont want combinations that have more than 100 days of difference @juanpa.arrivillaga — Martin Facts
– Martin Facts, Commented Mar 25, 2020 at 1:28

Mark · Accepted Answer · 2020-03-25 01:41:50Z

Rather than filtering in your loop, pass the combination iterator to filter(). It's a little hard to use your data since you didn't provide an example of what you have, but here's a minimal example that hopefully will give you enough of an idea.

With filter() you just give it a lambda function that returns True for the combinations you want and False for those you don't:

from itertools import combinations

values = list(range(10))

# all 5 element combinations of 0-9 such that the difference
# between the first and last is less than 6 
combos = filter(lambda e: e[4] - e[0] < 6, combinations(values, 5))

for row in combos:
    print(row, row[4] - row[0])

Prints:

(0, 1, 2, 3, 4) 4
(0, 1, 2, 3, 5) 5
(0, 1, 2, 4, 5) 5
(0, 1, 3, 4, 5) 5
(0, 2, 3, 4, 5) 5
(1, 2, 3, 4, 5) 4
(1, 2, 3, 4, 6) 5
(1, 2, 3, 5, 6) 5
...
(4, 5, 7, 8, 9) 5
(4, 6, 7, 8, 9) 5
(5, 6, 7, 8, 9) 4

Collectives™ on Stack Overflow

Conditions on itertools combinations Python

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related