filtering an array of object based on string array

Question

my problem might not be as challenging as some other similar questions but they were a little to much for me.

I have an array of objects that I need to filter by name against a string array of names, if the names match I want to remove the object with the name that matches

so like the following:

nameObjects = [{name: 'name3', value: 'some val'},{name: 'name1', value:'some other val'}]
names = ['name1','name2','name3']

I've tried the following just using for loops but I'm sure that there is a quicker (and correct lol) filter method that works

         for(i=0; i < this.names.length; i++){
            for(j=0; j < this.nameObjects.length; j++){

              if(this.names[i] === this.nameObjects[j].name){
                this.files.splice(i,this.nameObjects[j])
              }
            }
          }

also sorry for the poor logic ^

Shubham Khatri · Accepted Answer · 2020-06-02 16:11:00Z

3

You should not mutate the array while you are looping over it.

You can simply use Array.prototype.filter with Array.prototype.includes to get the desired result

const nameObjects = [{name: 'name3', value: 'some val'},{name: 'name1', value:'some other val'}];
const names = ['name2','name3'];
const res = nameObjects.filter(obj => !names.includes(obj.name));
console.log(res);

answered Jun 2, 2020 at 16:11

Shubham Khatri

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1 Comment

monsterpiece Over a year ago

I see, so take the opposite, thank you this worked out perfectly for me!

Nikita Madeev · Accepted Answer · 2020-06-02 16:10:16Z

1

const nameObjects = [
    { name: "name3", value: "some val" },
    { name: "name1", value: "some other val" },
];
const names = ["name1", "name2"];

const result = nameObjects.filter(obj => !names.includes(obj.name));

console.log(result);

answered Jun 2, 2020 at 16:10

Nikita Madeev

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