How to retrieve the url from background image using Selenium and Javascript

Question

I'm trying to retrieve the url from an background image with Xpath or Javascript, but with no luck for now. this is what I have

<div style="width: 100%; display: inline-block;">
 <div tws-article-images-preload="item" class="tws-article-images--preload ng-scope tws-article-images-- 
   image-small" ng-click="closeImage()" use-original="useOriginal" style="background-image: 
   url(&quot;https://i.pinimg.com/originals/59/54/b4/5954b408c66525ad932faa693a647e3f.jpg;);">
 </div>
</div>

And have tried this two with different modification

//*[starts-with(@style, 'background-image: url()] <--Did not work 

return document.getElementsByClassName('tws-article-images--preload ng-scope tws-article-images--image-small').src

Does this answer your question? How to get background image URL of an element using JavaScript? — DolUnity
– DolUnity, Commented Jun 18, 2020 at 22:05
Why is this tagged with f#? (I'll remove it, it doesn't seem to apply) — Abel
– Abel, Commented Jun 18, 2020 at 23:13

Felipe Zavan · Accepted Answer · 2020-06-18 23:58:33Z

1

document.getElementsByClassName('classname')[0].style.backgroundImage.slice(4, -1).replace(/"/g, "");

edited Jun 18, 2020 at 23:58

answered Jun 18, 2020 at 22:06

Felipe Zavan

1,8531 gold badge20 silver badges36 bronze badges

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2 Comments

Dymond Over a year ago

Yeah. I tried this earlier, but it gives me Cannot read property 'backgroundImage' of undefined

Felipe Zavan Over a year ago

@Dymond I edited my answer. Need to get the first item ([0]).

jahnavi13 · Accepted Answer · 2020-06-18 22:12:44Z

1

You can try

return document.getElementsByClassName('tws-article-images--preload ng-scope tws-article-images--image-small').style.backgroundImage.slice(4, -1).replace(/["']/g, "");

answered Jun 18, 2020 at 22:12

jahnavi13

424 bronze badges

Comments

E.Wiest · Accepted Answer · 2020-06-19 00:39:59Z

Your XPath expression is wrong (missing ' and a possible annoying CRLF). Fix it with :

//*[starts-with(@style, 'background-image:')]/@style

Then use regex to clean the result :

txt = 'background-image: url("https://i.pinimg.com/originals/59/54/b4/5954b408c66525ad932faa693a647e3f.jpg;);'
result = re.sub(r"^.+\"(.+?);.+", r"\1", txt)
print(result)

With XPath :

substring-after(substring-before(//*[starts-with(@style, 'background-image:')]/@style,';)'),'"')

Output : https://i.pinimg.com/originals/59/54/b4/5954b408c66525ad932faa693a647e3f.jpg

undetected Selenium · Accepted Answer · 2020-06-19 08:59:13Z

To retrieve the url from the background image you can usethe following solution:

Using slice():

var img = document.getElementsByClassName('tws-article-images--preload')[0],
style = img.currentStyle || window.getComputedStyle(img, false),
bgImage = style.backgroundImage.slice(4, -1).replace(/"/g, "");
//printing the url
console.log('Image URL: ' + bgImage);

Using regex:

var img = document.getElementsByClassName('tws-article-images--preload')[0],
style = img.currentStyle || window.getComputedStyle(img, false),
var url = backgroundImage.match(/url\(["']?([^"']*)["']?\)/)[1];
//printing the url
console.log('Image URL: ' + url);

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