jQuery - Create an array of objects using each

Question

I'm a jQuery newbie.

I have a simple form with n lines (although I'm not using html form):

<div id="myCities">
  <div class="line">City1: <input type="text" /></div>
  <div class="line">City2: <input type="text" /></div>
  <div class="line">City3: <input type="text" /></div>
  <button>Add Your Cities</button>
</div>

I have a javascript var called "users" with general users data:

var users = [
  { "username": "John", "year": 1999},
  more users...
]

When clicking on the button, I want to add an array of cities to the user's data (let's say we are working with John so he's [0])

I want the object to look like:

{ "username": "John",
  "year": 1999,
  "cities": [
    { "City1": $('.line input).val() },
    ... and so on for the 3 cities entered
  ]   
}

I tried using

$.each($('.line'), function() { 
   // but I'm not really sure what to put here 
});

Thanks!

When do you want to add the list of cities to the object? Will John click a "save" or "submit" button, or do you need to update it as he types, or something else? — hughes
– hughes, Commented Jul 25, 2011 at 14:08

ShankarSangoli · Accepted Answer · 2011-07-25 14:14:14Z

32

Try this

var cities = [];

var $this, input, text, obj;
$('.line').each(function() { 
   $this = $(this);
   $input = $this.find("input");
   text = $this.text();
   obj = {};
   obj[text] = $input.val();
   cities.push(obj);
});

users[0].cities = cities;

answered Jul 25, 2011 at 14:14

ShankarSangoli

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6 Comments

jfriend00 Over a year ago

Shouldn't you be using var on your local variables?

ShankarSangoli Over a year ago

If I define it inside each loop they will be defined for each iteration which is not required. For that reason I defined them outside the loop.

idophir Over a year ago

Although @marc's solution is much more elegant, I ended up using this solution. I believe it is more general and will be helpful for more people.

edison23 Over a year ago

btw, seems to me this is passing only a reference to object obj to the array, which means data in the objects get overwritten... I think...

LatentDenis Over a year ago

it should be var cities = new Array(); rather than var cities = []; because the latter won't let you push to it. The error will show saying .push is not a valid method.

|

marc · Accepted Answer · 2011-07-25 14:15:32Z

5

$.each($('.line'), function() { 
   var key = $(this).text().replace(/.*(City\d+).*/,'$1');
   user.cities[key] = $(this).find('input').val(); 
});

answered Jul 25, 2011 at 14:15

marc

6,2431 gold badge31 silver badges33 bronze badges

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